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m=y2−y1x2−x1=15−75−1=84=2y−y1=m(x−x1)⟺(x1,y1)=(1,7)y−7=2(x−1)y−7=2x−2y=2x−2+7 y=2x+5
Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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The equation would be .05x+50=100 Then you would solve for x
Answer:
<h2>The year is 2010.</h2>
Step-by-step explanation:
The population of wolves is given by P(t) = 80(0.98)t.
The study has began in the year of 2000 and will end in 2020.
The difference between 2000 and 2009 is 9 years and the difference between 2009 and 2020 is 11 years.
Hence, the maximum value of t is 11.
The domain is 
.
The population will be 80, that is P(t) = 80.
Hence, 0.98t = 1, or, t = 
≅1.
In (2009 + 1) = 2010, the population of wolves will be 80.
Answer: -3
Step-by-step explanation:
