3 years ago

Use the rational roots theorem to select values that are possible zeros of the function

1 answer:

8 0

Answer:

-3 and 3/2

Step-by-step explanation:

6x^3 - 2x^2 + x + 3

possible roots are p/q where p = factors of 3 and q are factors of 6

So from the 4 choices possible roots are -3 and 3/2

You might be interested in

professor190 [17]

Answer:

$160/5

Step-by-step explanation:

160/5 would be 32 and 315/9 would be 35. 32 is less than 35 so $160/5 would be the better deal.

3 0

3 years ago

pickupchik [31]

2x + 3 /12 = 2x/8
⇒ 48x/24 + 6/24 = 6x/24
⇒ (48x+ 6)/24= 6x/24
⇒ 48x+ 6 = 6x
⇒ 48x- 6x= -6
⇒ 42x= -6
⇒ x= -6/42
⇒ x= -1/7

x=-1/7~

6 0

4 years ago

kramer

Answer:

it is a linear expression

6 0

2 years ago

Flauer [41]

Answer:

$x^4/(2x^6)$

Explanation:

In the first example the division results in a radical, not a polynomial.

The remaining examples are not counter-examples (they do result in a polynomial)

8 0

3 years ago

aleksandrvk [35]

216/200=%
1.08 which equals 108%

4 0

4 years ago