All categories

3 years ago

Using the diagram, which two planes would intersect in HG ?

Mathematics

2 answers:

sdas [7]3 years ago

8 0

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

The figure of cuboid is given in the question.

we need to find the two planes that would intersect in HG.

B. ABCD and EFGH

EFGH contains HG whereas ABCD does not.

So, it can't get intersected in HG.

C. BCEF and ABCD

HG is not contained in both the planes.

D. ADHE and ABEF

HG is not contained in both the planes.

A. EFGH and CDHG

Both the planes contain HG.

so, it would intersect in HG.

Hence, Option 'A' is correct.

taurus [48]3 years ago

6 0

Answer:

A. EFGH and CDHG

Step-by-step explanation:

We have been given a diagram and we are asked to find which of the given planes would intersect in HG.

We can see from our diagram that HG is the common side for planes EFGH and CDHG. This means that planes EFGH amd CDHG intersect in HG.

Therefore, our answer will be planes EFGH and CDHG and option A is the correct choice.

You might be interested in

Please help meeee! please

ser-zykov [4K]

Answer:

A) 48.8

Step-by-step explanation:

the mean is: sum of all terms divided by number of terms

49 + 37 + 41 + 54 + 63= 244

244/ 5= 48.8

7 0

4 years ago

The local grocery store sells different sizes of peanut butter. Find the unit prices for each size container, and then identify

kumpel [21]

Answer:

0.35

0.30

0.33

28oz

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that

Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

$P(A\cap B)=P(A).P(B)$

Now, According to question , we can get that

$P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}$

So,

$P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}$

So, by using the conditional probability , which state that

$P(B\mid A)=\frac{P(A\cap B)}{P(A)}$

$P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}$

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

4 0

4 years ago

The width of the wading pool is 2.45m. Convert the width to centimeters.

lutik1710 [3]

Answer:

245

Step-by-step explanation:

1m-100cm

2.45m=2.45x100

5 0

2 years ago

A market analyst has projected that the cost of producing d dog leashes will be given by the polynomial 9000 + 3.2d. The revenue

Sholpan [36]

Answer:

C. $-0.00005d^2+11.8d-9000$

Step-by-step explanation:

Given:

Cost Price for producing 'd' dog lashes = $9000+3.2d$

Revenue Generated from selling 'd' dog lashes = $d(15-0.00005d)$

We need to find the profit earned from producing and selling 'd' dog lashes.

Solution:

Now we know that;

profit earned from producing and selling 'd' dog lashes can be calculated by Subtracting Cost Price for producing 'd' dog lashes from Revenue Generated from selling 'd' dog lashes.

framing in equation form we get;

Profit earned = $d(15-0.00005d)-(9000+3.2d)$

Now Applying Distributive property we get;

Profit earned = $15d-0.00005d^2-9000-3.2d$

Now Combining like terms we get;

Profit earned = $-0.00005d^2+15d-3.2d-9000$

Profit earned = $-0.00005d^2+11.8d-9000$

Hence Profit earned from producing and selling 'd' dog lashes is $-0.00005d^2+11.8d-9000$ .

3 0

3 years ago