Answer:
a)
And we can find this probability using the normal standard table or excel:
b)
And we can find this probability with this difference:
And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.
c)
And we can find this probability using the complement rule and the normal standard table or excel:
d) We can consider unusual events values above or below 2 deviations from the mean
![Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5](https://tex.z-dn.net/?f=%20Lower%20%3D%20%5Cmu%20-2%2A%5Csigma%20%3D%2021.1%20-2%2A5.3%20%3D10.5)
A value below 10.5 can be consider as unusual
![Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7](https://tex.z-dn.net/?f=%20Upper%20%3D%20%5Cmu%20%2B2%2A%5Csigma%20%3D%2021.1%20%2B2%2A5.3%20%3D31.7)
A value abovr 31.7 can be consider as unusual
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part a
Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the normal standard table or excel:
Part b
And we can find this probability with this difference:
And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.
Part c
And we can find this probability using the complement rule and the normal standard table or excel:
Part d
We can consider unusual events values above or below 2 deviations from the mean
![Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5](https://tex.z-dn.net/?f=%20Lower%20%3D%20%5Cmu%20-2%2A%5Csigma%20%3D%2021.1%20-2%2A5.3%20%3D10.5)
A value below 10.5 can be consider as unusual
![Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7](https://tex.z-dn.net/?f=%20Upper%20%3D%20%5Cmu%20%2B2%2A%5Csigma%20%3D%2021.1%20%2B2%2A5.3%20%3D31.7)
A value abovr 31.7 can be consider as unusual