Answer:
I think B and C are the only ones true
FOR THE FIRST PROBLEM:
Differentiating p^2 + 2q^2 = 1100 with respect to time => 2p(dp/dt) + 4q(dq/dt) = 0
<span>dp/dt = -2q/p(dq/dt) </span>
<span>R = pq </span>
<span>dR/dt = p(dq/dt) + q(dp/dt) = -p²/2q(dp/dt) + q(dp/dt) = (2q² - 1100)/2q * (dp/dt) + q(dp/dt) </span>
<span>A = (2q - 550/q)
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17. 8/10 is equal to .8 not .08
18a. False
18b. True
18c. False
18d. False
18e. True
19. 0.02
20. No, the zero needs to be in the tenths place or else the decimal (.2) would become 2/10.
21. 17/100
22. Words- Ten hundredths
Fraction- 10/100
Decimal- .10
Given:
1/2 loaf of bread
3 friends
1/2 ÷ 3 ⇒ 1/2 * 1/3 = 1*1 / 2*3 = 1/6
In dividing fractions, get the reciprocal of the divisor and multiply it to the dividend
Answer: Option B is the cheaper deal (the 12 batteries for $14.76)
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Explanation:
For the first deal we can say
3 batteries = 4.80 dollars
3/3 batteries = 4.80/3 dollars .... divide both sides by 3
1 battery = 1.60 dollars
The unit price for the first deal is $1.60 per battery.
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For the second deal we could say
12 batteries = 14.76 dollars
12/12 batteries = 14.76/12 dollars .... divide both sides by 12
1 battery = 1.23 dollars
The unit price for the first deal is $1.23 per battery.
This is the cheaper deal.
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So in short, you're dividing the total cost over the number of items to get the unit price.
