Answer:
Step-by-step explanation:
Let x represent the number of years it will take the two colleges to have the same enrollment.
In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. This means that the expected number of students at college A in x years time is
12900 + 900x
In the same year, there were 25,000 students at college B, with a projected enrollment decline of 700 students per year. This means that the expected number of students at college B in x years time is
25000 - 700x
For both colleges to have the same enrollment,
12900 + 900x = 25000 - 700x
900x + 700x = 25000 - 12900
1600x = 12100
x = 12100/1600
x = 7.56
Approximately 8 years
The year would be 2000 + 8 = 2008
Answer:
x^4/21
Step-by-step explanation:
Answer:
a. 24.9476 Kg.
b. The safe daily dosage range is between 2494760 units /day and 6236900 units/day
c. Yes
Step-by-step explanation:
a. Lets see the convertion from lb to Kg:
- 1 Lb= 0.453592
- 55 lb = 0.453592*55= 24.9476 kg
b. Minimum daily dosage is 100,000 units /kg
- For this kid: 100,000 * 24.9476= 2,494,760 units/ day
- in 6 dosis; 2494760/6= 415,793.33 units every 4 hours
Maximun daily dosage is 250,000 units /kg
- For this kid: 250,000 * 24.9476= 6,236,900 units/ day
- in 6 dosis; 6,236,900/6= 1,039,483.33 units every 4 hours
c: Yes, because 525.000 units every 4 hours is between the minimun and maximun dosaje for this kid
Answer:
x = .140741
Step-by-step explanation:
0.7(3x−0.2)=0.3(0.8−2x)
Distribute
.7 * 3x - .7*.2 = .3*.8 - .3 * 2x
2.1x - .14 = .24 - .6x
Add .6x to each side
2.1x +.6x -.14 = .24 -.6x+.6x
2.7x -.14 = .24
Add .14 to each side
2.7x -.14+.14 = .24+.14
2.7x = .38
Divide by 2.7 on each side
2.7x/2.7 = .38/2.7
x = .140741
