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4 years ago

Select the graph of the equation below. y= -1/4x^2+1

Mathematics

1 answer:

V125BC [204]4 years ago

4 0

Answer:

Step-by-step explanation:

Since you have the different parabolas there, the simplest way to determine which one is, is replacing x as 0 and then y as 0

y = -1/4x^2 + 1

When x = 0

y = -1/4 (0)^2 +1 = 1

When y = 0

0 = -1/4x^2 +1

1/4 x^2 = 1

x^2 = 4

x = + 2

x = - 2

The parabola with points:

(0,1); (-2,0) and (2,0) is a.

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Find the value of x & z plz and give an explanation ( :

inessss [21]

Answer:

x = 6√2
x = √3

Step-by-step explanation:

1. You have correctly written the relationship between the side lengths and the length of the hypotenuse for these isosceles right triangles.

For this problem, you simply need to multiply the side length by √2. The length of the hypotenuse is then ...

x = 6√2

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2. The side length multiplied by √2 is √6. You know

√6 = √(2·3) = (√2)(√3) = (√2) · (side length)

so we know that x = √3.

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4 years ago

What is the answer ?

k0ka [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

I need help what is the answer

alukav5142 [94]

Answer:

245

Step-by-step explanation:

To find the value of a function at a specific point you can substitute that point into the equation.

For the function $f(x)=\frac{1}{5}(3-x)^{2}$ , the specific point would be substituted in for every x in the equation.

$f(-32)=\frac{1}{5} (3-(-32))^{2}=\frac{1}{5}(35)^{2}=\frac{1225}{5}=245$

8 0

3 years ago

Read 2 more answers

What are the roots of 2x^2+10×-48=0

mojhsa [17]

X=-8,3.
divide all terms by the two in the first term to get x^2+5x-24=0. Then find the factors. To do so, find what two numbers can be multiplied to get 24, and whether those two numbers can be added or subtracted to get the middle term (5). Since 8x(-3)=24 and 8-3=5, (x+8) and (x-3) are the factors. Then set the factors equal to zero. Add or subtract these numbers to the other side of the equation and you then get x=-8,3. These are the roots.

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3 years ago

A survey report states that 70% of adult women visit their doctors for a physical examination at least once in two years. If 20

irakobra [83]

Answer:

a) 0.3921 = 39.21% probability that fewer than 14 of them have had a physical examination in the past two years.

b) 0.107 = 10.7% probability that at least 17 of them have had a physical examination in the past two years.

Step-by-step explanation:

For each women, there are only two possible outcomes. Either they visit their doctors for a physical examination at least once in two years, or they do not. The probability of a woman visiting their doctor at least once in this period is independent of any other women. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of adult women visit their doctors for a physical examination at least once in two years.

This means that $p = 0.7$

20 adult women

This means that $n = 20$

(a) Fewer than 14 of them have had a physical examination in the past two years.

This is:

$P(X < 14) = 1 - P(X \geq 14)$

In which

$P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 14) = C_{20,14}.(0.7)^{14}.(0.3)^{6} = 0.1916$

$P(X = 15) = C_{20,15}.(0.7)^{15}.(0.3)^{5} = 0.1789$

$P(X = 16) = C_{20,16}.(0.7)^{16}.(0.3)^{4} = 0.1304$

$P(X = 17) = C_{20,14}.(0.7)^{17}.(0.3)^{3} = 0.0716$

$P(X = 18) = C_{20,18}.(0.7)^{18}.(0.3)^{2} = 0.0278$

$P(X = 19) = C_{20,19}.(0.7)^{19}.(0.3)^{1} = 0.0068$

$P(X = 20) = C_{20,20}.(0.7)^{20}.(0.3)^{0} = 0.0008$

$P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1916 + 0.1789 + 0.1304 + 0.0716 + 0.0278 + 0.0068 + 0.0008 = 0.6079$

$P(X < 14) = 1 - P(X \geq 14) = 1 - 0.6079 = 0.3921$

0.3921 = 39.21% probability that fewer than 14 of them have had a physical examination in the past two years.

(b) At least 17 of them have had a physical examination in the past two years

$P(X \geq 17) = P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

From the values found in item (a).

$P(X \geq 17) = P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0716 + 0.0278 + 0.0068 + 0.0008 = 0.107$

0.107 = 10.7% probability that at least 17 of them have had a physical examination in the past two years.

6 0

3 years ago