Select the graph of the equation below. y= -1/4x^2+1

Mathematics

1 answer:

V125BC [204]3 years ago

4 0

Answer:

Step-by-step explanation:

Since you have the different parabolas there, the simplest way to determine which one is, is replacing x as 0 and then y as 0

y = -1/4x^2 + 1

When x = 0

y = -1/4 (0)^2 +1 = 1

When y = 0

0 = -1/4x^2 +1

1/4 x^2 = 1

x^2 = 4

x = + 2

x = - 2

The parabola with points:

(0,1); (-2,0) and (2,0) is a.

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2. what value of b makes the following equation true

Svetradugi [14.3K]

Answer:

2. 10

3. D. 1 for all n

Step-by-step explanation:

2. The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^b = 1/a^-b

$\dfrac{4^8}{(4^2)^{-3}}\div 4^4=\dfrac{4^8}{4^{-6}\cdot4^4}=\dfrac{4^8}{4^{-2}}\\\\=4^8\cdot4^2=4^{10}$

The value of n is 10.

3. Using the above rules of exponents, the expression simplifies to ...

6^(-n+n) = 6^0 = 1

The value is 1 for any n.

4 0

3 years ago

A line passes through the points (2,4) and (5,6) . Select Yes or No to tell whether each equation describes this line. Equation

krek1111 [17]

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