Answer:
I hope it helps u
Step-by-step explanation:
Let's solve your system by elimination.
15j+12k=18;5j+4k=6
Multiply the second equation by -3, then add the equations together.
(15j+12k=18)
−3(5j+4k=6)
Becomes:
15j+12k=18
−15j−12k=−18
Add these equations to eliminate j:
0=0
Answer:
Infinitely many solutions
Note: Please Brain-list it ok dear!
If u have any doubt you can ask ok
Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
The sides are 2, 1, 1.5, and 2.5 clockwise
The two numbers that multiply to 196 and add to -28 are: -14 and -14.
-14 * -14 = 196
-14 + -14 = -28
It should be d which is 45
