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4 years ago

PLEASE HELP! I WILL GET A ZERO!!!

Mathematics

1 answer:

Katen [24]4 years ago

5 0

10.5
Step by Step Solution:
Lower extreme is 5
Median is 9
Upper Extreme is 12
Quartile 1 is 8
Quartile 3 is 10.5

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Pls help. Multiply 2/3×7/12×9/14

worty [1.4K]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

Approach 1 (trickier)

$\frac{2}{3}*\frac{7}{12}*\frac{9}{14}\\ \\ \frac{2*7*9}{3*12*14}\\ \\ \frac{126}{504}\\ \\\frac{1}{4}$

Approach 2 (easier)

$\frac{2}{3}*\frac{7}{12}*\frac{9}{14}\\\\\frac{2}{14}*\frac{7}{12}*\frac{9}{3}\\ \\ \frac{1}{7}*\frac{7}{12}*3\\ \\ \frac{1}{12}*3\\ \\ \frac{3}{12}\\ \\\frac{1}{4}$

6 0

2 years ago

Read 2 more answers

Which equation is equivalent to...

Taya2010 [7]

I believe it’s the first one. sorry if i’m
wrong :)

5 0

3 years ago

Read 2 more answers

You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig

brilliants [131]

Answer:

Confidence interval

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$

And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

We can calculate the mean and the deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$\bar X= 8.98[/tex[tex]s = 1.29$

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=12-1=11$

The Confidence level is 0.95 or 95%, the value of significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value would be $t_{\alpha/2}=2.20$

Repplacing the info we got:

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$ And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

7 0

3 years ago

PLEASE HELP!

kompoz [17]

The first and the third ones is true

4 0

4 years ago

The volume of a cone varies jointly as the height of the cone and the area of the base. The volume of a cone with height 30 cent

irina [24]

Answer:

V₂=28cm³

Step-by-step explanation:

Way 1

The volume of a cone is $V=\frac{\pi r^{2}h}{3}$ , and h₁ = 30 cm but the base (Ba₁) is 14 cm², so

$V=\frac{Ba.h}{3}$ , where Ba= Base area

if h₂=7cm and Ba₂=12cm² then

$V_{1} =\frac{12cm^{2}.7cm}{3}=28cm^{3}$

Way2

If the volume of a cone varies jointly as the height of the cone and the area of the base, then we must find the relationship between the bases and heights of the cones

Ba₁*h₁ = 30cm*14cm² = 420cm³

Ba²*h²= 7cm*12cm² = 84cm³

420/84 = 5; ratio = 5 also

V₂=V₁/5 ⇒ V₂=140cm³/5 = 28cm³

8 0

3 years ago

Read 2 more answers