A+bi is a complex number
(3+2i)(a+bi)=17+7i
remember
i²=-1
so
expand and solve
a is the ral part
bi is the imaginary part
ok so
if Ac+Be=dc+fe where c=c and e=e then A=d and B=f
(3+2i)(a+bi)=17+7i
expand/distribute/FOIL
3a+2ai+3bi+2bi²=17+7i
3a+2bi+2ai+2bi=17+7i
3a-2b+2ai+2bi=17+7i
real parts are 3a-2b
imaginary is 2ai+2bi
so
3a-2b=17 and
2ai+2bi=7i
we need to solve
2nd equation, divide both sides by i
2a+2b=7
multiply by -1 and add to other equation
3a+2b=17
<u>-2a-2b=-7 +</u>
1a+0b=10
a=10
subsitue
2a+2b=7
2(10)+2b=7
20+2b=7
2b=-13
b=-13/2
the complex number is
10-(13/2)i or
10-6.5i
Answer:
C is correct
Step-by-step explanation:
-3(2b+9) + 5 (-5b+ 6)
-6b-27 -25b +30
-31b+3
Answer:
g
Step-by-step explanation:
x goes to f m to 5 :-)
Answer:
In an equation, the two expressions are deemed equal which is shown by the symbol =. Where as in an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥. ... If the statement is true, the number is a solution to the equation or inequality.
Step-by-step explanation:
Ok so the first step would be to distribute 3 into 3x and -6. So 3 times 3x would be 9x. 3 times -6 is -18.
the equation now is
18 = 9x - 18
Now you would have to do inverse operation
18 = 9x - 18
+18 +18
36 = 9x
Now you would divide 9x into 36 to isolate the variable
36 / 9x = 4
x = 4
