Un cometa es visible desde la tierra cada 24 años y otro, cada 36 años. El último año que fueron visibles conjuntamente fue en 1
1 answer:
Answer:
Ambos cometas coincidirán en 2016.
Step-by-step explanation:
(The following exercise is presented in Spanish and for such reason explanation will be held in that language).
Sean y
los años en los que se hacen visibles los cometas, respectivamente. Se sabe que los cometas coinciden cuando se pueden ver el mismo año, ese año estaría asociado al mínimo común múltiplo de ambos intervalos de tiempo, el cual sería igual a 72 años. Entonces, ambos cometas volverán a coincidir en 2016.
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There is no question in Part A, but i do what i can.
Part A.
We know that:
n - number of <span>packets of crackers
p -</span> <span>number of packets of pretzels
p = 2n+9
s - </span><span>number of packets of peanuts
s = 3p = 3(2n+9) = 6n+27
So:
There are 42 </span><span>packets of crackers, 93 </span><span>packets of pretzels and 279 packets of peanuts.
Part B.
x - number of rows with exactly 2 </span><span>passengers
y </span>- number of rows with exactly 3 <span>passengers
and:
There are </span><span>12 rows with exactly 2 passengers and 36 rows with exactly 3 passengers.</span>
Part A.
We know that:
n - number of <span>packets of crackers
p -</span> <span>number of packets of pretzels
p = 2n+9
s - </span><span>number of packets of peanuts
s = 3p = 3(2n+9) = 6n+27
So:
There are 42 </span><span>packets of crackers, 93 </span><span>packets of pretzels and 279 packets of peanuts.
Part B.
x - number of rows with exactly 2 </span><span>passengers
y </span>- number of rows with exactly 3 <span>passengers
and:
There are </span><span>12 rows with exactly 2 passengers and 36 rows with exactly 3 passengers.</span>