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3 years ago

Find the missing side of each triangle. leave your answers in simplest radical form

Mathematics

1 answer:

Marysya12 [62]3 years ago

6 0

By the Pythagorean theorem
.. x = √((2√3)^2 -(√6)^2) = √(12 -6) = √6 . . . . cm

x = √6 cm

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I need help . With 1a 1b and 2. The answer are correct but how do you get to the answer

djyliett [7]

If you need help the first one is go put your number + bye the 500 and that is answer for 1a do the second one I hope that helps

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3 years ago

A kinder garden class has 9 girls and 11 boys in class what percent of the class are girls

ivolga24 [154]

Answer:

45%

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the solution to the following equation 4(-2x+3)=10x-15

saul85 [17]

$4(2x + 3) = 10x - 15 \\ \\ 1. \: - 8x + 12 = 10x - 15 \\ 2. \: 12 = 10x - 15 + 8x \\ 3. \: 12 = 18x - 15 \\ 4. \: 12 + 15 = 18x \\ 5. \: 27 = 18x \\ 6. \: \frac{27}{18} = x \\ 7. \: \frac{3}{2} = x \\ 8. \: x = \frac{3}{2}$

3 0

3 years ago

Show that 1 2/3 + 2 3/4 = 4 5/12

lozanna [386]

2/3x4 =8/12
3/4x3 =9/12

8/12+9/12=17/12
17/12=1 5/12

1+2+1 5/12 = 4 5/12

5 0

3 years ago

The ratio of the circumference of two circles is 3:2.What is the ratio of their area

Nezavi [6.7K]

The ratio of their area is 9/4

<h2>Explanation:</h2>

We use ratios to compares values. In this exercise, we are comparing the circumference of two circles, which is:

$3:2$

and we want to know what is the ratio of their area. Recall that the circumference of a circle is given by:

$C=2\pi r \\ \\ \\ Where: \\ \\ C:Circumference \\ \\ r:Radius \ of \ the \ circle$

If we define:

$C_{1}: \ Circumference \ of \ circle \ 1 \\ \\ C_{2}: \ Circumference \ of \ circle \ 2 \\ \\ r_{1}: \ Radius \ of \ circle \ 1 \\ \\ r_{2}: \ Radius \ of \ circle \ 2$

Then, the ratio of the circumference of two circles is 3:2 is:

$\frac{C_{1}}{C_{2}}=\frac{2\pi r_{1}}{2\pi r_{2}}=\frac{3}{2} \\ \\ \therefore \frac{r_{1}}{r_{2}}=\frac{3}{2}$

The area of a circle is given by:

$A=\pi r^2 \\ \\ A:Area \\ \\ r:Radius$

So the ratio of their area can be found as:

$\frac{A_{1}}{A_{2}}=\frac{\pi r_{1}^2}{\pi r_{2}^2} \\ \\ \\ A_{1}:Area \ of \ circle \ 1 \\ \\ A_{2}:Area \ of \ circle \ 2$

So:

$\frac{A_{1}}{A_{2}}=\frac{r_{1}^2}{r_{2}^2}=\left( \frac{r_{1}}{r_{2}} \right)^2 \\ \\ \frac{A_{1}}{A_{2}}=\left(\frac{3}{2}\right)^2 \\ \\ \boxed{\frac{A_{1}}{A_{2}}=\frac{9}{4}}$

<h2>Learn more:</h2>

Unit rate: brainly.com/question/13771948#

#LearnWithBrainly

5 0

3 years ago