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cricket20 [7]
3 years ago
6

If a bar chart showed that 4 students received an a on the test, 3 students received a b, and 1 student received a c, the talles

t bar on the chart would be for the a column.
Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

The tallest bar on the chart would be for the a column of 4 students received an A  on the test

Step-by-step explanation:

The tallest bar on the chart would be for the a column of 4 students received an A  on the test.

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Express the improper fraction as a mixed number in simplest form.<br> 39/8
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mixed number: 4 7/8       simplest form: (THERE IS NONE)

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A study of one thousand teens found that the number of hours they spend on social networking sites each week is normally distrib
jek_recluse [69]
The z-value that corresponds to a two-tailed 95% confidence interval is z = +/- 1.96. Then the bounds of the confidence interval can be determined as:
Lower bound = mean - z*SD/sqrt(n) = 20 - 1.96*2/sqrt(100) = 20 - 0.12 = 19.88 hours
Upper bound = mean + z*SD/sqrt(n) = 20 + 1.96*2/sqrt(100) = 20 + 0.12 = 20.12 hours
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7 0
3 years ago
Identify the standard form of the equation by completing the square.
OLEGan [10]

Answer:

\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1

Step-by-step explanation:

<u>Given equation</u>:

4x^2-9y^2-8x+36y-68=0

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

\implies 4x^2-8x-9y^2+36y=68

Factor out the coefficient of the x² term and the y² term.

\implies 4(x^2-2x)-9(y^2-4y)=68

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2

\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36

Factor the two perfect trinomials on the left side:

\implies 4(x-1)^2-9(y-2)^2=36

Divide both sides by the number of the right side so the right side equals 1:

\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}

Simplify:

\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1

Therefore, this is the standard equation for a horizontal hyperbola with:

  • center = (1, 2)
  • vertices = (-2, 2) and (4, 2)
  • co-vertices = (1, 0) and (1, 4)
  • \textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}
  • \textsf{Foci}: \quad  (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)

4 0
2 years ago
Will give brainliest !Select the correct answer.
QveST [7]

Answer:

im not sure but i think c.

hope this helped !

Step-by-step explanation:

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3 years ago
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a marble is drawn at random from a bag which contains nine yellow marbles and six white marbles . Find the probability of white
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Answer:

2/5

Step-by-step explanation:

4 0
3 years ago
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