The answer to this question is a=2
Answer: E - S = (-16 and 6)
Step-by-step explanation:1/3 of the 30 decimals in T have an even tenths digit, it follows that 1/3*(30)=10 decimals in T have an even tenths digit.
Hence: Te =list of 10 decimals
Se = sum of all 10 decimals in Te
Ee =estimated sum of all 10 decimals in Te after rounding up.
Remaining 20 decimals in T all have an odd tenths digits.
To =list of this 20 decimals
So = sum of all 20 decimals in To
Eo = estimated sum of 20 decimals in To
Hence,
E = Ee + Eo and S =Se +So, hence:
E-S, =(Ee+Eo) - (Se+So) =(Ee-Se) +(Eo-So)
Ee-Se >10 (0.1)=1
S=10(1.8)+20(1.9) =18+38=56
E=10(2)+20(1)=40
E-S =40-56=-16.
AlsoS=10(1.2)+20(1.1)=34
E=10(2)+20(1)=40
E-S=40-34=6
Answer:
Because theres nothing to solve for x is all real numbers
Step-by-step explanation:
There is no way to solve it as theres nothing to solve for. You just plug in the x's with any number you want and it still will be there
Step-by-step explanation:
We need to use the binomial theorem/Pascal's triangle here.
(a+b)^5 = (5 choose 0)a^5 + (5 choose 1)a^4*b + (5 choose 2)a^3*b^2 + (5 choose 3)a^2*b^3 + (5 choose 4)a*b^4 + (5 choose 5)b^5.
5 choose 0 = 1
5 choose 1 = 5
5 choose 2 = 10
5 choose 3 = 10
5 choose 4 = 5
5 choose 5 = 1
And 1, 5, 10, 10, 5, 1, is the (5+1) = 6th row of pascal's triangle.
Therefore we get
g^5 + 5g^4*2 + 10g^3*2^2 + 10g^2*2^3 + 5g*2^4 + 2^5
which is
g^4 + 10g^4 + 40g^3 + 80g^2 + 80g + 32
Or, you could do the slow way, by just doing (g+2)(g+2)(g+2)(g+2)(g+2)
