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Ilya [14]
3 years ago
8

Find the area of the shaded regions:

Mathematics
2 answers:
ASHA 777 [7]3 years ago
6 0
The answer is 41 degrees
White raven [17]3 years ago
4 0

Answer:

41 Degrees

Step-by-step explanation:

So basically you add the 72 and the other 72 to get 148.You obviously know the angle in between 72 and 72 is a right angle or 90 degrees.Then you add 148 and 90 to get 238.Then 360 - 238 is 122.Now you know all the angles.So we have to ask ourselves what is 148/360 simplified.It is 37/90.Now that we know that and we know that the radius is 10.We have to find the regular area which is 10 times 10 which is 100.Finally we need to figure out what part of 100 is 37/90 and it is 41.111111111111.Rounded it is 41.

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A rectangle has a height of 4cm and a width of 8cm what is the area
aleksley [76]

Answer: 32

Step-by-step explanation:

4cm × 8cm = 32cm

5 0
4 years ago
Please help me if you can thank you.
Zielflug [23.3K]
Let the three consecutive odd numbers be x,x+2,x+4.
Given, their sum =219

Therefore, x+x+2+x+4=219
⇒3x+6=219
Subtract 6 from both the sides,
⇒3x+6−6=219−6

⇒3x=213
⇒x=71
The other numbers are x+2=71+2=73 and x+4=71+4=75.

Therefore, threee odd numbers are 71,73 and 75.
7 0
3 years ago
Read 2 more answers
I need help with adding complex numbers
Usimov [2.4K]

For example:

Find: (3-i)+(2+3i) by graphing

Step 1: Graph 3-i and 2+3i on the complex plane. Connect each of these numbers to the origin with a line segment.


4 0
3 years ago
In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE║ AB. Find the measures of the angles of ΔABC, if m∠ADE: m∠ADB = 2
drek231 [11]

Answer:   ∠A=48°,∠B=48°,∠C=84°.


Step by-step explanation:

Given:  AD and BE are the angle bisectors  of ∠A and ∠B

i.e ∠6=∠7    ( ∵ Angles formed after  AD bisected ∠A)

∠4=∠5       ( ∵ Angles formed after  BE bisected ∠B)

Also,  DE║AB

⇒ ∠2=∠7   (∵ Alternate interior angles)

   ∠3=∠6   (∵ Alternate interior angles)

And ∠ADE : ∠ADB =∠2:∠3= 2:9 =2x : 9x     ..(1)

To Find:  ∠A,∠B,∠C.

Solution:  ∠2=∠7 (∵ Given)    ...(2)

∠2=∠4  (∵ angles on the same segment)    ...(3)

∠4=∠5 =∠B/2 (∵ Given)    ...(4)

∴ In Δ ABD

∠3+∠4+∠5+∠7 = 180 (∵ Sum of interior angles of a triangle)

From equation 2,3,4,5, Put values

9x+2x+2x+2x =180°

⇒15x = 180°

⇒x=12°

Putting values in equation (4) ⇒ ∠ B =2*(2*12) = 48°

Also, <u>∠B=∠A=48°</u>

Now,in Δ ABC

∠C+∠B+∠A= 180°

⇒48°+48°+∠C= 180°

<u><em>⇒∠C=84°</em></u>

6 0
4 years ago
Solve for x !<br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%2B%205x%20%2B%206%20%3D%200" id="TexFormula1" titl
Alina [70]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve for x ~

\qquad \sf  \dashrightarrow \: {x}^{2}  + 5x + 6 = 0

\qquad \sf  \dashrightarrow \: {x}^{2}  + 3x + 2x + 6 = 0

\qquad \sf  \dashrightarrow \: {x}^{}(  x+ 3) + 2(x + 3)= 0

\qquad \sf  \dashrightarrow \: {}^{}(  x+ 2)(x + 3)= 0

\begin{cases} \sf \: x =  - 2 \:  \:  \:  \:  \:  \:  \: \sf if \: (x + 2) = 0 \\  \\  \sf \: x =  - 3 \:  \:  \:  \:  \:  \:  \: if \: (x + 3) = 0\end{cases}

I hope that helps ~

8 0
2 years ago
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