Question

Please help! functions operations. explain please

Answer 1

Answer:

$f^{-1}(x)=x^2-3$

Step-by-step explanation:

Given $f(x)=\sqrt{x+3}$

Let $y=\sqrt{x+3}$

Interchange x and y

$x=\sqrt{y+3}$

Solve for y, by first squaring both sides

$x^2=y+3$

$x^2-3=y$

Hence

$f^{-1}(x)=x^2-3$

The last choice is correct