Please help! functions operations. explain please

Mathematics

1 answer:

Lina20 [59]3 years ago

5 0

Answer:

$f^{-1}(x)=x^2-3$

Step-by-step explanation:

Given $f(x)=\sqrt{x+3}$

Let $y=\sqrt{x+3}$

Interchange x and y

$x=\sqrt{y+3}$

Solve for y, by first squaring both sides

$x^2=y+3$

$x^2-3=y$

Hence

$f^{-1}(x)=x^2-3$

The last choice is correct

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Ede4ka [16]

X = 4.

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12x + 8 =60

Subtract the 8 from 60 to simplify the equation.

12x = 48

Divide 12 by 48 and get 4.

x=4

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3 years ago

I need help (please show your work)

oksano4ka [1.4K]

Answer:

the solution is (-4, 3)

Step-by-step explanation:

if you were to graph y = -7/4x - 4 you could plot your first point at (0, -4) and get your second point by going up 7 units (from (0, -4) and to the left by 4

if you were to graph y = -1/4x + 2 you could plot your first point at (0, 2) and get your second point by going up 1 unit (from (0, 2) and to the left by 4

the second point plotted for each equation will be the point of intersection, (-4, 3)

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3 years ago

Arithmetic of functions

Rzqust [24]

Its B.

If $f(x)=4x+1$ and $g(x)=x^2-5$ then, $(\frac{g}{f})(x)=\frac{x^2-5}{4x+1}$ and $x\neq-\frac{1}{4}$ because if x were $-\frac{1}{4}$ then you would have division by 0.