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3 years ago

How do i solve (x+3)^1/2=(3x+7)^1/4

1 answer:

6 0

Step 1: Cross-multiply.
(x+3)^1/2=(3x+7)^1/4
Step 2: Subtract 6x from both sides.
4x+12−6x=6x+14−6x
−2x+12=14
Step 3: Subtract 12 from both sides.
−2x+12−12=14−12
−2x=2
Step 4: Divide both sides by -2.
−2x/−2=2/−2

Answer:
x=−1

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3 years ago

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3 years ago

Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$

$P(X\leq3) =0.944444369992\approx 0.94$

Hence, the required probability is 0.94

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3 years ago