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3 years ago

How many terms are in the expression 4a + 3b + c

Mathematics

2 answers:

Ludmilka [50]3 years ago

4 0

3 terms

https://youtu.be/0sq2PMQ_Nak
use that video to help you.

Grace [21]3 years ago

3 0

3 4a is one term 3b is another term and the test is the 3rd term

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MaRussiya [10]

7 multiplied by 1/4.

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3 years ago

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Help I’m almost out of time

VladimirAG [237]

Answer: First option.

Step-by-step explanation:

You can idenfity in the figure that $\angle FCE$ is formed by two secants that intersect outside of the given circle.

It is important to remember that, by definition:

$Angle\ formed\ by\ two\ Secants=\frac{1}{2}( Difference\ of\ intercepted\ Arcs)$

Knowing this, you can set up the following equation:

$m\angle FCE=\frac{1}{2}(BD-FE)$

Therefore, you must substitute values into the equation and then evaluate, in order to find the measure of the angle $\angle FCE$ .

This is:

$m\angle FCE=\frac{1}{2}(112\°-38\°)\\\\m\angle FCE=37\°$

6 0

3 years ago

The reflection of the point (4, 6) over the y-axis is:

Brums [2.3K]

(-4,6)
The x value changes bc since it is a reflection y cannot change and x becomes negative

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2 years ago

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-8.46 greater or less than 5.31

Gekata [30.6K]

Hello.

-8.46 is less than 5.31, because it is negative.

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3 years ago

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Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(

Inessa05 [86]

Answer:

$2+i$

Step-by-step explanation:

Given the expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

To find:

The expression of above complex number in standard form $a+bi$ .

Solution:

First of all, learn the concept of $i$ (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by $i$ .

Value of $i =\sqrt{-1}$ .

Now, let us consider the given expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i$

So, the given expression in standard form is $2+i$ .

Let us compare with standard form $a+bi$ so we get $a =2, b =1$ .

$\therefore$ The standard form of

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

is: $\bold{2+i}$

8 0

3 years ago