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Nat2105 [25]
3 years ago
13

How many terms are in the expression 4a + 3b + c

Mathematics
2 answers:
Ludmilka [50]3 years ago
4 0
3 terms

https://youtu.be/0sq2PMQ_Nak
use that video to help you.
Grace [21]3 years ago
3 0
3 4a is one term 3b is another term and the test is the 3rd term
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In a movie theater, the first row contains 3 seats, the second row contains 6 seats, the third row contains 9 seats, and the fou
yanalaym [24]

Answer:It's an arithmetic sequence with a common difference, d, = 4

A1 = 8

A2 = 8+4 = 12

A3 = 12+4 = 16   = 8+4(3-1) = 8+4(2) = 8+8

AN = A1 + d(N-1)

AN = 8 +4(N-1)  =  the Nth term in the sequence

Step-by-step explanation: hoped it helped

7 0
3 years ago
The function f(x)=501170(0.98)x gives the population of a Texas City x years after 1995. What was the population in 1995?
galina1969 [7]

Answer:

The population of a Texas City in 1,995 was 501,170\ people

Step-by-step explanation:

we have

f(x)=501,170(0.98^{x})

we know that

The population in 1,995 is for x=0

so

substitute the value of x=0 in the function f(x)

f(0)=501,170(0.98^{0})=501,170\ people

4 0
4 years ago
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Step-by-step explanation:

4 0
3 years ago
What is the least common multiple of the two denominators between 6/8 and 4/32
Nostrana [21]

Answer:4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
At the mall, buying a pair of shoes and buying a book are independent events.The probability that a shopper buys shoes is 0.20.
Goryan [66]

Answer: Probability that a shopper buys shoes and a book is 0.02.

Step-by-step explanation:

Since we have given that

Event A : Buying a pair of shoes

Event B:  Buying a book

Since A and B are independent events.

Probability that a shopper buys shoes i.e.

P(A) = 0.20

Probability that a shopper buys a book i.e.

P(B)=0.10

So, we need to find the probability that a shopper buys shoes and a book is given by

P(A\ and\ B)=P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=0.20\times 0.10\\\\P(A\cap B)=0.02

Hence, Probability that a shopper buys shoes and a book is 0.02.

3 0
3 years ago
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