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netineya [11]
3 years ago
7

Find the surface area of the composite solid.

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

We have:

4 triangles with the base b = 5ft and the height h = 6ft

4 rectangles with the lenght l = 5ft and the width w = 4ft

1 square with side a = 5ft.

The formula of an area of a riangle:

A_T=\dfrac{1}{2}bh

Substitute:

A_T=\dfrac{1}{2}(5)(6)=\dfrac{1}{2}(30)=15\ ft^2

The formula of an area of a rectangle:

A_R=lw

Substitute:

A_R=(5)(4)=20\ ft^2

The formula of an area of a square:

A_S=a^2

Substitute:

A_S=5^2=25\ ft^2

The Surface Area of composite solid:

SA=4A_T+4A_R+A_S

Substitute:

SA=4(15)+4(20)+25=60+80+25=165\ ft^2

<h3>Answer: The Surface Area of the composite solid is 165 ft².</h3>
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<u>Let's review few rules before solving.</u>

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Solution (9):

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Solution (11):

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Solution (15):

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Solution (17):

  • 1/2⁰ = 1/1 = 1

Solution (26):

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Solution (36):

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Hoped this helped!

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Given that <img src="https://tex.z-dn.net/?f=I_0%20%3D%2010%5E-12" id="TexFormula1" title="I_0 = 10^-12" alt="I_0 = 10^-12" alig
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The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².

Since we require I, making I subject of the formula, we have

dB/10 = log₁₀(I/I₀)

\frac{I}{I_{0} } = 10^{\frac{dB}{10} } \\I = I_{0} 10^{\frac{dB}{10} }

Substituting the values of the variables into the equation, we have

I = I_{0} 10^{\frac{dB}{10} }\\I = 10^{-12} 10^{\frac{156}{10} }\\I = 10^{-12} 10^{15.6}\\I = 10^{15.6-12} \\I = 10^{3.6} W/m^{2}

I = 3981.072W/m²

I = 3.981 × 10³ W/m²

So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Learn more about intensity of sound here:

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