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blondinia [14]
3 years ago
6

A dilation has a center (0,0,0), Find the image fo the point (-1, -2, 0) for the scale factor of 3.

Mathematics
1 answer:
pychu [463]3 years ago
7 0

Answer:

(- 3, - 6, 0)

Step-by-step explanation:

Since the dilatation is centred at the origin, multiply each of the coordinates by the scale factor 3

(- 1, - 2, 0) → (- 3, - 6, 0)


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We must divide the total height by the size of the blocks to work out how many are in the tower
22.5 / 1.5 = 15 blocks
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What value should replace the "?" to make the equations parallel?
Otrada [13]
The same slope would make the equations parallel. Therefore 5/3 would make them parallel.
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Solve -5(3n + 4) = 40.
Sveta_85 [38]
N=-4
Distribute the -5
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3 0
2 years ago
10 points, doing this one again because I got a wrong answer last time but regardless thank you for trying to help​
Alik [6]

Hey ! there

Answer:

  • Value of missing side i.e. TE is <u>1</u><u>2</u><u> </u><u>feet</u>

Step-by-step explanation:

In this question we are provided with a <u>right</u><u> </u><u>angle </u><u>triangle</u> having <u>TS </u><u>-</u><u> </u><u>35</u><u> </u><u>ft </u><u>and</u><u> </u><u>SE </u><u>-</u><u> </u><u>37</u><u> </u><u>ft </u>. And we are asked to find the missing side that is <u>TE </u>using Pythagorean Theorem .

<u>Pythagorean Theorem :</u> -

According to Pythagorean Theorem sum of squares of perpendicular and base is equal to square of hypotenuse in a right angle triangle i.e.

  • H² = P² + B²

<u>Where </u><u>,</u>

  • H refers to <u>Hypotenuse</u>

  • P refers to <u>Perpendicular</u>

  • B refers to <u>Base</u>

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

In the given triangle ,

  • Base = <u>TE </u>

  • Perpendicular = <u>TS </u><u>(</u><u> </u><u>35</u><u> </u><u>feet </u><u>)</u>

  • Hypotenuse = <u>SE </u><u>(</u><u> </u><u>37</u><u> </u><u>feet </u><u>)</u>

Now applying Pythagorean Theorem :

\quad \longmapsto \qquad \:SE {}^{2}  = TS {}^{2}  + TE {}^{2}

Substituting values :

\quad \longmapsto \qquad \:37 {}^{2}  = 35 {}^{2}  + TE {}^{2}

Simplifying it ,

\quad \longmapsto \qquad \:1369 = 1225  + TE {}^{2}

Subtracting 1225 on both sides :

\quad \longmapsto \qquad \:1369 - 1225  = \cancel{1225}  + TE {}^{2}  -  \cancel{1225}

We get ,

\quad \longmapsto \qquad \:144 = TE {}^{2}

Applying square root to both sides :

\quad \longmapsto \qquad \ \sqrt{ 144} =  \sqrt{TE {}^{2}}

We get ,

\quad \longmapsto \qquad \:     \red{\underline{\boxed{\frak{TE  = 12 \: feet}}}} \quad \bigstar

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>value </u><u>of </u><u>missing </u><u>side </u><u>is </u><em><u>1</u></em><em><u>2</u></em><em><u> </u></em><em><u>feet </u></em><em><u>.</u></em>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are verifying our answer using Pythagorean Theorem . We know that according to Pythagorean Theorem ,

  • SE² = TS² + TE²

Substituting value of SE , TS and TE :

  • 37² = 35² + <u>1</u><u>2</u><u>²</u>

  • 1369 = 1225 + 144

  • 1369 = 1369

  • L.H.S = R.H.S

  • Hence , Verified .

<u>Therefore</u><u> </u><u>,</u><u> </u><u>our</u><u> answer</u><u> is</u><u> correct</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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Lucy wants to be exempt from her semester exam. In order for that to happen, she has to average an 85 over 3 test grades. Her fi
anastassius [24]

Answer:

<em>Grades to be scored in 3rd exam = 88</em>

Step-by-step explanation:

Given that average of 3 numbers is 85.

First two numbers are 81 and 86.

To find:

3rd number so that average is 85

Solution:

Let the third number = x

Formula for average is:

Average = \dfrac{Sum\ of\ numbers}{Total\ count\ of\ numbers}

Here, sum of numbers = 81+86+x =167+x

Total count of numbers = 3

85 = \dfrac{167+x}{3}\\\Rightarrow x=255-167\\\Rightarrow \bold{x=88}

<em>Grades to be scored in 3rd exam = 88</em>

8 0
3 years ago
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