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3 years ago

Alexia set up the tent below in case it rained during the barbecue.

Mathematics

1 answer:

kherson [118]3 years ago

4 0

Answer:

Is this the question you are trying to ask?

-Alexia set up the tent below in case it rained during the barbecue.Which equation shows how to determine the volume of the tent?-

Bc this doesn't even have a question mark. "Alexia set up the tent below in case it rained during the barbecue." haha

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Mr. Lee gave his four children $25.40 to share equally. How much money did each child get?

Len [333]

Answer: the answer is 6.38

Step-by-step explanation: You have to divide 25.40/4 you can use base ten blocks or draw it out or just divide that is how i got the answer!

4 0

2 years ago

One store has carrots on sale for $1.1 for 3 pounds, while another store has carrots on sale for $0.78 for two pounds. Which sto

irina1246 [14]

Answer:

1) The store selling for 1.1 per 3 lbs

2) $6.24

Step-by-step explanation:

1.1/3 = 0.37

0.78/2 = 0.39

0.37 is cheaper so it's a better deal

$\frac{0.78}{3} =\frac{x}{24} \\\\3x=18.72\\x=6.24$

4 0

3 years ago

Read 2 more answers

Abc bookstore sells new books, n, for $12, used books, u, for $8, and magazines, m, for $5 each. The store earned $340 revenue l

poizon [28]

Answer:

The number of new books sold = 10

The number of used books sold (u) = 15

The number of magazines sold (m) = 20

Step-by-step explanation:

Let us assume the number of new books = n

So, the number of used books sold (u) = New books sold + 5 = n + 5

Also, the number of magazines sold (m) = 2 x ( Number of new books sold)

= 2 n

⇒ u = n + 5, m = 2 n

Here, the cost of each new book n- = $12

So, the cost of n new books = n x ($12) = 12 n

the cost of each used book u = $8

So, the cost of u = (n+ 5) used books = n+5 x ($8) = 8 n + 40

the cost of each magazine m = $5

So, the cost of m = (2n ) magazines = 2n x ($5) = 10 n

Also, total earnings = $340

⇒ 12 n + 8n +40 + 10 n = 340

or, 30 n = 300

or,n = 300/30 = 10

Hence the number of new books sold = n = 10

The number of used books sold (u) = n + 5 = 15

The number of magazines sold = m = 2 n = 20

4 0

2 years ago

Pls answer, and be clear on which one your answering, thank youuu!! Very thankful worth 30 points!! :) <333

sveta [45]

The mistake Shawna made was in her answer the 54 repeats so the bar should be over the .54 not the .545

7 0

3 years ago

The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit

Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52$

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

$Median=(\frac{n+1}{2})^{th}\ obs.$

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

$Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation$

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

$Range =Maximum-Minimum\\=69-36\\=33$

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

$IQR=Q_{3}-Q_{1}\\=60-44\\=16$

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

$s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143$

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

$s=\sqrt{s^{2}}=\sqrt{100.143}=10.01$

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

$Q_{1}-1.5QR=44-1.5\times 16=20$

Compute the value of Q₃ + 1.5 IQR as follows:

$Q_{3}+1.5QR=60-1.5\times 16=80$

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

6 0

3 years ago

Alexia set up the tent below in case it rained during the barbecue.​

Alexia set up the tent below in case it rained during the barbecue.