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dem82 [27]
3 years ago
14

Find the y intercepts I'll mark the brainliest​

Mathematics
1 answer:
vivado [14]3 years ago
7 0

Answer:

1. (0,-2)

2. (0,8)

3. (0,7)

4. (0 , \frac{1}{2})

5. (0,-3.5)

6. (0,-4)

7. (0,0)

8. (0,-4)

9. (0,5)

10. (0,0)

Step-by-step explanation:

there are 10 boxes in total, slope is y = mx + b

the slope is always the constant.

constant: number without a variable.

y - intercept:

y = mx + <u>b</u>

<u>if there is nothing after the slope it means the y -intercept is 0</u>

<u><em>The Kid Laroi</em></u>

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Suzy has a collection of quarters and dimes. Together she has 44 coins worth $6.95. How many quarters and how many dimes does Su
OverLord2011 [107]
X = quarters
y = dimes

0.25x + 0.10y = 6.95 or 25x + 10y = 695
x + y = 44

25x + 10y = 695
25 (x + y = 44)

25x + 10y = 695

25x + 25y = 1,100

-15y = -405
y = 27 dimes
and 17 quarters
6 0
3 years ago
What is the equation of a line with a slope of -2 that passes through the point (-2,12)?
slavikrds [6]

Answer:

y=-2x + 8 which is the required equation

Which is option C

Step-by-step explanation:

Given:

Slope = m = -2

Given points are ( -2,12)

Which is

x = -2 and y =12

TO find:

Equation of line passing through these points = ?

Solution:

The point slope form of a line is

y = mx + c

Here we don't know the value of c

To find it

Putting y = 12 , x= -2 and y = -2 in the given equation

y = mx + c

Putting values it becomes

12 = (-2)*(-2) + c

12 = 4 + c

Subtracting 4 from both sides

12-4 = 4 -4 + c

8 = c

Now we have

m = -2 and c= 8

So equation of a line is given by

y = mx + c

Putting value of m and c

y = -2*x + 8

y=-2x + 8 which is the required equation


7 0
2 years ago
Read 2 more answers
Can someone please answer all the questions with explanations?
aalyn [17]

Answer:

I don't know sorry can't help you

6 0
2 years ago
Read 2 more answers
US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter
Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

           Standard deviation = 112

           Mean = 505

           Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

H_0:\mu \geq 477\\H_a:\mu < 477

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

z=\frac{505-477}{\frac{112}{\sqrt{64}}}

z=2

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0
3 years ago
The only time the word 'incorrectly' isn't spelled incorrectly is when it's spelled incorrectly. (⊙_ ⊙)
Korvikt [17]

ahaha good one

Step-by-step explanation:

...........

3 0
3 years ago
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