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alexira [117]
3 years ago
6

Composition of the function is commuatative

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

The functions g and f are said to commute with each other if g ∘ f = f ∘ g. Commutativity is a special property, attained only by particular functions, and often in special circumstances. For example, |x| + 3 = |x + 3| only when x ≥ 0. ... The composition of one-to-one functions is always one-to-one.

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Mr. Cruise drove 70 miles in March he drove seven times as many miles in March as he did in January he drove four times as many
SVEN [57.7K]
70/7= 10 miles in January
10/4 = 2.5 miles in February
5 0
3 years ago
Convert 12 and a half of 30
tamaranim1 [39]

Answer:

375

Step-by-step explanation:

12½[30] → 25⁄2[30]

Multiply 25 by 30 [750] then divide by 2 to get 375.

I am joyous to assist you anytime.

7 0
3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
Graph the equation y = -3x on a graph
Dafna1 [17]

Put a dot on the -3 from the y-axis and draw a straight line from left to right.

3 0
3 years ago
Which graph represents the function y = cos(4x)?<br><br> Answer is graph B
VARVARA [1.3K]

Answer:

Step-by-step explanation:

Let the equation of the cosine function is,

y = Acos(Bx)

From the graph attached,

A = Amplitude = \frac{1-(-1)}{2}

   = 1

B = \frac{2\pi}{\text{Period}}

B = \frac{2\pi}{\frac{\pi}{2}-0}

B = \frac{4\pi}{\pi}

B = 4

Therefore, equation of the cosine wave given in the graph will be,

y = 1.Cos(4x)

y = Cos(4x)

7 0
3 years ago
Read 2 more answers
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