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6 - -4 = 10
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Answer:
58 in
Step-by-step explanation:
The fact that the rectangles are congruent means both have a length of 18 in and a width of 11 in. The perimeter is ...
P = 2(L +W)
P = 2(18 in + 11 in) = 2(29 in)
P = 58 in
The perimeter of KHGJ is 58 inches.
If angle AEC is 90° and angle AEB bisects it and is 45° that right there proves that angle AEB bisects angle AEC
Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
Answer: x = 2a over b + c
Step-by-step explanation:
1. Multiply both sides by two. This cancels out 2 and turns a into 2a. It should look like 2a = bx + cx
2) Since both b and c have x’s, we turn it into (b + c)x
3. Then divide both sides by b+c to get 2a over b + c = x
