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aivan3 [116]
3 years ago
13

How did the Robber Baron's and the industry they created reflect the image of the Gilded age?

Advanced Placement (AP)
1 answer:
ioda3 years ago
3 0

Answer:

The Gilded Age was a period in American history In which a chunk of its citizens were made wealthy . This gave rise to the people called the robber barons who became wealthy as a result of their monopoly on some sectors of the economy and became an integral part of society. Some examples of robber barons include John D. Rockefeller, Andrew Carnegie, and JP Morgan.

They were known to live a very lavish lifestyle due to their fortunes.

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A 16th century religious movement that attempted to reform the Roman Catholic Church
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How to find out whether or not if the line is parallel,intersecting,perpendicular or coincident
slava [35]

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Explanation:

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1 year ago
Two heads are better than one. Two is company, three is a crowd. These two sentences are... similar in meaning opposite in meani
Andrew [12]

Answer:

Neither the same nor the opposite

Explanation:

<em>Two heads are better than one</em> is an idiom meaning that it's easier to solve a problem or come up with an idea with the help of another person than alone.

<em>Two is company, three is a crowd </em>is an idiom usually associated with a romantic context. It's used to say that a third person should leave when two people (e.g. lovers) want to be together on their own.

So, when we compare these explanations, we can't say that these two sentences mean the same, nor the opposite.

6 0
3 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
WILL MARK BRAINLESTTTT
yulyashka [42]

Answer:

B

Explanation:

5 0
3 years ago
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