Question

HELP me PLS ASAP Write the following expressions as one fraction: (7x+4/8y) − (3x−1/6y)

Answer 1

$\dfrac{7x+4}{8y}-\dfrac{3x-1}{6y}\\\\\text{common denominator is 24y}\\\\=\dfrac{(3)(7x+4)}{(3)(8y)}-\dfrac{(4)(3x-1)}{(4)(6y)}\\\\\text{use distributive property}\\\\=\dfrac{(3)(7x)+(3)(4)}{24y}-\dfrac{(4)(3x)+(4)(-1)}{24y}\\\\=\dfrac{21x+12}{24y}-\dfrac{12x-4}{24y}\\\\=\dfrac{21x+12-(12x-4)}{24y}\\\\=\dfrac{21x+12-12x+4}{24y}\\\\\text{combine like terms}\\\\=\dfrac{(21x-12x)+(12+4)}{24y}\\\\=\boxed{\dfrac{9x+16}{24y}}$