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Nastasia [14]
3 years ago
8

Can someone explain this ​

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0
8+12=20
20+12=32
Just keep adding by 12
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[Shapes]<br>How many degrees is ZA’BC in this cube?<br>please help me i don't understand​
Galina-37 [17]
Yeah same idekkk but obviously each side is 90 degrees bc it’s a 90 degree angle
5 0
3 years ago
I can identify and use inverses to solve equations with one variable
Naddik [55]

Answer:

\boxed{g = 0.0278}

Step-by-step explanation:

\boxed{question \: 3.} \\   \frac{2}{3}  = 5 \sqrt{g}  -  \frac{1}{6}  \\ 4= 30 \sqrt{g }  - 1 \\ 30 \sqrt{g}  = 5 \\  \sqrt{g}  =  \frac{5}{30}  \\ g =  \frac{ {5}^{2} }{ {30}^{2} }  =  \frac{25}{900}  \\ g =  \frac{1}{36}  = 0.0277777778 \\ \boxed{ g = 0.0277777778}

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7 0
3 years ago
I need help finding the values of the last boxes shown in the image.
Bingel [31]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid revolution on the X-axis?</h3>

The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

In the graph, the given straight line passes through two points (0,0) and (2,8).

Therefore, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

where:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Now

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

5 0
2 years ago
How can you determine which property of equality is needed to isolate a variable and solve a given equation? Explain. A. Use inv
mamaluj [8]

Answer:

A. Use inverse relationships to "undo" the operation.

Step-by-step explanation:

I took the , and this was the correct answer. :)

6 0
3 years ago
Read 2 more answers
What divides a two dimensional shape into two congruent shapes​
zaharov [31]

Answer:

Rectangle is a 2dimensional shape so, let me explain using it

The diagonal of a rectangle divides the rectangle into two triangles that are congruent and they are the same size and shape.

Another example is parallelogram

The diagonal of a parallelogram also divides the figure into two triangles that are congruent.

Step-by-step explanation:

6 0
4 years ago
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