Question

Ignore the circled one and actually try please​

Answer 1

Answer:

a.$\frac{x^3-4x^2}{3x+15}$

Step-by-step explanation:

$\huge{ \frac{2x^4}{x+5} \div \frac{6x^2}{x-4} }\\\\\huge{= \frac{2x^4}{x+5} \times \frac{x-4}{6x^2}}\\\\\huge{ =\frac{x^2}{x+5} \times \frac{x-4}{3}}\\\\\huge {=\frac{x^2(x-4)}{3(x+5)}}\\\\\huge{=\frac{x^3-4x^2}{3x+15}}$

Answer 2

Answer:

A

Step-by-step explanation:

= 2x5−8x4 /(6x3+30x2)

=  2x3−8x2 /(6x+30 )

= x3−4x2 /(3x+15)