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3 years ago

Ignore the circled one and actually try please

Mathematics

2 answers:

Vesna [10]3 years ago

6 0

Answer:

a. $\frac{x^3-4x^2}{3x+15}$

Step-by-step explanation:

$\huge{ \frac{2x^4}{x+5} \div \frac{6x^2}{x-4} }\\\\\huge{= \frac{2x^4}{x+5} \times \frac{x-4}{6x^2}}\\\\\huge{ =\frac{x^2}{x+5} \times \frac{x-4}{3}}\\\\\huge {=\frac{x^2(x-4)}{3(x+5)}}\\\\\huge{=\frac{x^3-4x^2}{3x+15}}$

scoray [572]3 years ago

4 0

Answer:

Step-by-step explanation:

= 2x5−8x4 /(6x3+30x2)

= 2x3−8x2 /(6x+30 )

= x3−4x2 /(3x+15)

You might be interested in

Find the surface area. PLEASE HELP!!!!!

jonny [76]

Since it is a cube, all sides lengths are the same.

Surface area = 2lw+2lw+2hw
if you substitute all the sides for 13 you get
2(169) three times
so you multiply and get 338 three times so you do 338x3 which is 1014 cm

its messy to explain so i attached a photo

7 0

2 years ago

The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has an approximate normal distribution wi

lord [1]

Answer:

The approximate proportion of 1-mile long roadways with potholes numbering between 20 and 70 is 0.9735.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 50, standard deviation = 10.

Between 20 and 70.

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above.

20 = 50 - 3*10

So 20 is 3 standard deviations below the mean. Of the 50% of the measures below the mean, 99.7% are within 3 standard deviations of the mean, that is, above 20.

70 = 50 + 2*10

So 70 is 2 standard deviations above the mean. Of the 50% of the measures above the mean, 95% are within 2 standard deviations of the mean, that is, below 70.

Percentage:

0.997*50% + 0.95*50% = 97.35%

As a proportion, 97.35%/100 = 0.9735.

The approximate proportion of 1-mile long roadways with potholes numbering between 20 and 70 is 0.9735.

3 0

3 years ago

3. What is the present value of single cash flow of $25,000 received at the end of 10 years, if we asume a discount rate of 5% a

Alexandra [31]

Answer:

5% Discount: $14,968.42

7% Discount: $12,099.56

Step-by-step explanation:

Since the discount rate is being compounded annually we can go ahead and use the Exponential Growth Formula, or in this case we will actually be using the Exponential Decay Formula since we are compounding a discount rate

$D = a*(1-r)^{t}$

Where:

D is the present value
a is the initial cash flow
r is the discount rate in decimal form
t is the span of time

Since we are looking for the present value in 10 years with a rate of 5%, we can plug these values into the formula and solve for D.

$D = 25000*(1-0.05)^{10}$

$D = 25000*(0.95)^{10}$

$D = 25000*0.5987$

$D = 14,968.42$

So the Present day value at 5% discount rate is $14,968.42 .

Now we can solve the equation at a 7% discount rate.

$D = 25000*(1-0.07)^{10}$

$D = 25000*(0.93)^{10}$

$D = 25000*0.48398$

$D = 12,099.56$

So the Present day value at 7% discount rate is $12,099.56

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

7 0

4 years ago

The total area under the standard normal curve to the left of zequalsnegative 1 or to the right of zequals1 is

In-s [12.5K]

Answer:

0.3174

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the area under the normal curve to the left of Z. Subtracting 1 by the pvalue, we find the area under the normal curve to the right of Z.

Left of z = -1

z = -1 has a pvalue of 0.1587

So the area under the standard normal curve to the left of z = -1 is 0.1587

Right of z = 1

z = 1 has a pvalue of 0.8413

1 - 0.8413 = 0.1587

So the area under the standard normal curve to the right of z = 1 is 0.1587

Left of z = -1 or right of z = 1

0.1587 + 0.1587 = 0.3174

The area is 0.3174

5 0

4 years ago

Which equations could be used to solve for the unknown lengths of AABC? Check all that apply.

bearhunter [10]

Given that ABC is a right triangle.

The measure of ∠A is 45° and AB = 9

We need to determine the equations that could be used to solve the unknown lengths of ΔABC

Option A: $\sin \left(45^{\circ}\right)=\frac{BC}{9}$

The length of BC can be determined using the trigonometric ratios.

$sin\ \theta=\frac{opp}{hyp}$

where $\theta=45^{\circ}$ , $opp= BC$ and $hyp = 9$

Hence, substituting the values, we get;

$\sin \left(45^{\circ}\right)=\frac{BC}{9}$

Hence, Option A is the correct answer.

Option B: $\sin \left(45^{\circ}\right)=\frac{9}{BC}$

The length of BC can be determined using the trigonometric ratios.

$sin\ \theta=\frac{opp}{hyp}$

where $\theta=45^{\circ}$ , $opp= BC$ and $hyp = 9$

Hence, substituting the values, we get;

$\sin \left(45^{\circ}\right)=\frac{BC}{9}$

Thus, the length of BC can be determined using $\sin \left(45^{\circ}\right)=\frac{BC}{9}$

Hence, Option B is not the correct answer.

Option C: $9 \tan \left(45^{\circ}\right)=A C$

The length of AC can be determined using the trigonometric ratios.

$tan \ \theta= \frac{opp}{adj}$

where $\theta=45^{\circ}$ , $opp= BC$ and $adj=AC$

Substituting the values, we get;

$tan \ 45^{\circ}=\frac{BC}{AC}$

Thus, the length of AC using the trigonometric ratios is $tan \ 45^{\circ}=\frac{BC}{AC}$

Hence, Option C is not the correct answer.

Option D: $(A C) \sin \left(45^{\circ}\right)=B C$

The formula for $sin \ \theta$ is given by the formula,

$sin\ \theta=\frac{opp}{hyp}$

where $\theta=45^{\circ}$ , $opp= BC$ and $hyp = 9$

Hence, substituting the values, we get;

$\sin \left(45^{\circ}\right)=\frac{BC}{9}$

Thus, the given equation $(A C) \sin \left(45^{\circ}\right)=B C$ is wrong.

Hence, Option D is not the correct answer.

Option E: $\cos \left(45^{\circ}\right)=\frac{BC}{9}$

The formula for $cos \ \theta$ is given by the formula,

$cos \ \theta=\frac{adj}{hyp}$

where $\theta=45^{\circ}$ , $adj=AC$ and $hyp = 9$

Substituting the values, we get;

$\cos \left(45^{\circ}\right)=\frac{AC}{9}$

Hence, the given equation $\cos \left(45^{\circ}\right)=\frac{BC}{9}$ is not possible.

Thus, Option E is not the correct answer.

8 0

3 years ago

Ignore the circled one and actually try please​

Ignore the circled one and actually try please