Answer:
The sum of the first five classroom numbers in a row is 5k + 20
Step-by-step explanation:
Since the smallest classroom number on the side of the building is numbered k and each consecutive odd integer is separated by a difference of
2.
Therefore:
k is the first class room.
k + 2 is the second class room.
k + 4 is the third class room.
k + 6 is the third class room.
k + 8 is the fifth class room.
The sum of the five consecutive class rooms are given as:
k + (k + 2) + (k + 4) + (k + 6) + (k + 8)
collecting alike terms we get
= k + k + k + k + k + 2 + 4 + 6 + 8
= 5k + 20
Therefore, The sum of the first five classroom numbers in a row is 5k + 20.
-30-6r=36
We move all terms to the left:
-30-6r-(36)=0
We add all the numbers together, and all the variables
-6r-66=0
We move all terms containing r to the left, all other terms to the right
-6r=66
r=66/-6
r=-11
Answer:
26
Step-by-step explanation:
12-8=4
3(4)=12
12/2=6
6*5=30
30-4
26
