How to factor 2x^2+xy-3y^2

Mathematics

1 answer:

frozen [14]3 years ago

6 0

Answer: (x−y)(2x+3y)

Step-by-step explanation: Check picture :)

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Oxana [17]

1/2x=-5 is the answer

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3 years ago

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Gnesinka [82]

A.
the y intercept is where x=0
x represents the number of months
when the number of months is 0, that is the initial number of games won

that looks to be a little below y=2, so maybe y=1.8?
the y intercept is y≈1.8
it represents the number of games won with 0 months of practice

B.
we can use y=mx+b
m=slope
b=y intercept
we know the y intercept
find the slope
slope=rise/run
the I'm going from x=0 to x=10
the rise is about 18.95 (from 1.8 to 20.75)
the run is 10
so slope would be 18.95/10=1.895

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A party tent is used for an outdoor event. Ropes of equal length support each tent pole. The angle the rope makes with the floor

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Law of sines can be used to solve this problem:

(note - let x represent the missing side length.)

1. set up proportion.
sin 90°/25 = sin 55°/x

2. solve.
(x) sin 90° = (25) sin 55°

(x) sin 90 °/sin 90° = (25) sin 55° / sin 90°

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A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medica

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Answer:

The sample mean is of 1925 calories.

The margin of error is of 75 calories.

The sample standard deviation is of 109.7992 calories.

Step-by-step explanation:

Sample mean:

The sample mean is the mean value of the two bounds of the confidence interval. So

$M = \frac{1850 + 2000}{2} = 1925$

The sample mean is of 1925 calories.

The margin of error

Difference between the bounds and the sample mean. So

2000 - 1925 = 1925 - 1850 = 75 calories.

The margin of error is of 75 calories.

Sample standard deviation:

Here, I am going to expand on the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 18 - 1 = 17

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 17 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.898