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Taya2010 [7]
3 years ago
10

Jacob runs 5 miles in 1 1/2 hours . Robert runs 3 miles in 45 minutes or 3/4 hour. Who runs faster

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

Robert

Step-by-step explanation:

If Robert runs 3 miles in 45 minutes, by the end of 90minutes, Robert would have covered 6miles, while Jacob covered 5miles in 90 minutes, therefore, Robert ran faster than Jacob.

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Cada uno
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Fun fact

An apple, potato, and onion all taste the same if you eat them with your nose plugged

Step-by-step explanation:

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Which is true of dependent events?
insens350 [35]

Answer:

Might be

Step-by-step explanation:

A.) The probability of all dependent events can be calculated using the OR formula

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The following table gives annual life insurance premiums per $1,000 of face value. Use the table to determine the face value of
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the answer is c.

$85,274.94

Step-by-step explanation:

on edge

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3 years ago
14. Mason bought a cell phone online for $89.99. He saw the same phone in a store for $118.99.
bazaltina [42]

Answer:

I'm gonna have to say False

Step-by-step explanation:

when you round to the nearest tenth you get 90 and 119. 119 - 90 is 29 not 29.99

8 0
3 years ago
In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe
enot [183]

Answer:

a)

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that \pi = 0.16

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = z\sqrt{\frac{0.16*0.84}{n}}

0.03\sqrt{n} = z\sqrt{0.16*0.84}

\sqrt{n} = \frac{z\sqrt{0.16*0.84}}{0.03}

(\sqrt{n})^2 = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

Question b:

99% confidence level,

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{2.575\sqrt{0.16*0.84}}{0.03})^2

n = 990.2

Rounding up

A sample size of 991 is needed.

8 0
3 years ago
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