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Vitek1552 [10]
3 years ago
9

The price of a gallon of gasoline was $1.65. The price rose y dollars. Then the price dropped $0.15 and later rose again by $0.4

5.
Which expression could be used to find the price of the gasoline?
Mathematics
2 answers:
Olenka [21]3 years ago
4 0

1.65 + y - .15 + .45 = price of gasoline

Fantom [35]3 years ago
3 0

Answer:1.95+y

Step-by-step explanation:

i forgot how to get to it lol

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Ethan ate 1/2 of it and had more equal parts.
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3 years ago
Solve 13+x>11. Enter your answer as an equality
Wittaler [7]

Answer:

x>-2

Step-by-step explanation:

13+x>11

Subtract 13 from each side

13-13+x>11-13

x>-2

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What is the inverse operation of division?
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The answer is D, Multiplication
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Two surfers and statistics students collected data on the number of days on which surfers surfed in the last month for 30 longbo
Alisiya [41]

Answer:

Do not reject H0. The mean days surfed for longboarders is significantly larger than the mean days surfed for all shortboarders

Step-by-step explanation:

The null hypothesis is that  the mean days surfed for all long boarders is larger than the mean days surfed for all short boarders

H0:  μL > μs      against the claim Ha:  μL≤ μs

the alternate hypothesis is the mean days surfed for all long boarders isless or equal to  the mean days surfed for all short boarders (because long boards can go out in many different surfing conditions)

The test statistic is

t= x1- x2/  √s1/n1+ s2/n2

1) Calculations

Longboards

Mean

ˉx=∑x/n=4+8+9+4+9+7+9+6+6+11+15+13+16+12+10+12+18+20+15+10+15+19+21+9+22+19+23+13+12+10/30

=377/30

=12.5667

Longboard Variance S2=[∑dx²-(∑dx)²/n]/n-1

=[831-(-13)²/30]/29

=831-5.6333/29

=825.3667/29

=28.4609

Shortboard Mean

ˉx=∑x/n=6+4+6+6+7+7+7+10+4+6+7+5+8+9+4+15+13+9+12+11+12+13+9+11+13+15+9+19+20+11/30

=288/30

=9.6

Shortboard Variance S2=[∑x²-(∑x)²/n]/n-1

=[ 3270-(288)2/30]/29

=3270-2764.8/29

=505.2/29

=17.4207

2) Putting values in the test statistic

t=|x1-x2|/√S²1/n1+S²2/n2

t =|12.5667-9.6|/√28.4609/30+17.4207/30

t =|2.9667|/√0.9487+0.5807

t=|2.9667|/√1.5294

t=|2.9667|/1.2367

t=2.3989

3) Degree of freedom =n1+n2-2=30+30-2=58

4) The critical region is t ≤ t(0.05) (58) =1.6716

5) Since the calculated t= 2.4 does not fall in the critical region t(0.05) (58)  ≤ 1.6716 we do not reject H0.

The p-value is 0.008969. The result is significant at p <0 .05.

6 0
3 years ago
What is 68.797 rounded to the nearest hundredth
yarga [219]
68.80 because 7 is greater than 5
3 0
3 years ago
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