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1 answer:
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Answer:
The answer is x = 5.
Step-by-step explanation:
Given:
Δ ABC is an Isosceles triangle with AB = CA
m∠ ABC = ( 6x + 4 )°
m∠ BAC = 73°
m∠ BCA = ( 8y - 7 )°
To Find:
x = ?
Solution:
Properties of an Isosceles Triangle.
- Base angles or two angles are equal.
- Any two sides are equal.
Here , Δ ABC is an Isosceles triangle with AB = CA
∴ m∠ BAC = m∠ BCA
∴ m∠ BCA = ( 8y - 7 )°
= 8 × 10 - 7
m∠ BCA = 73 Which is same as ∠ CAB
Property of a Triangle is Sum of the measures of the angle of a triangle is 180°.
Substituting the values we get,
The answer is x = 5.
Answer:
The cost of plastering the four wall at the rate of Rs 20 per meter square is Rs 3,543.4
Step-by-step explanation:
Given as :
The cost of carpeting a room = Rs 64,000
The rate of carpeting = Rs 540 m²
The breadth is twice its height
The length is twice its breadth
Let The length = L m
The breadth = B m
The height = L m
So, according to question
L = 2 B and B = 2 H
Now, Area of rectangular carpet = Length × Breadth
Or, A = L × B
Or, A = 2 B × B
∵ The cost of carpeting at the rate of Rs 540 per m² = Rs 64,000
So, area =
Or, 2× B² = 118.518
Or, B² =
Or, B² = 59.259
I,.e B = = 7.69 m
The length = 2 B
I.e L = 2 × 7.69 = 15.38 m
and H =
I.e H = = 3.84 m
So, Length = 15.38 m , Breadth = 7.69 m , height = 3.84 m
∵ The area of four wall = 2× ( Length + Breadth ) × height
or, The area of four wall = 2× ( 15.38 + 7.69 ) × 3.84
Or, The area of four wall = 177.17 m²
Now The rate of plastering the four wall = Rs 20 per square meter
So, The cost of plastering the four wall = area of four wall × rs 20
∴ The cost of plastering the four wall = 177.17 × Rs 20
I.e The cost of plastering the four wall = Rs 3,543.4
Hence The cost of plastering the four wall at the rate of Rs 20 per meter square is Rs 3,543.4 answer