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3 years ago

12

Equivalent ratio of 64:60

2 answers:

Snowcat [4.5K]3 years ago

5 0

An equivalent ratio of 64:60 is 16:15.

Sonja [21]3 years ago

5 0

To get an equivalent ratio, you are going to simplify it like you would a fraction. An equivalent ratio would be 32:30. Then, just keep dividing both sides by the same number until both sides can't be divided by the same number. i.e. 9:6 -> 3:2 Both sides were divided by three.

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3 years ago

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gladu [14]

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3 years ago

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4 years ago

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0.9 of Karen's Science score is equal to 0.75 of her Math score and 0.8 of her Chemistry score. Given that Karen scored 96 marks

DochEvi [55]

You have to formulate equations for this problem.

Let S = Science score

M = Math score

C = Chemistry score

To illustrate the given:

0.9S = 0.75M

0.9S = 0.8C

You are given that Karen’s Math score is 96 marks. You have to substitute the Math score to the first equation.

0.9S = 0.75(96)

0.9S = 72

S = 80

Therefore, Karen’s Science score is 80. Now, you have to substitute the Science score to the second equation.

0.9(80) = 0.8C

0.8C = 72

C = 90

So, Karen’s Chemistry score is 90.

Therefore, the total score of the 3 subjects is 266 (96 + 80 + 90).

5 0

4 years ago

Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?

saw5 [17]

The value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

$(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4$

Evaluate the combination factors.

So, we have:

$(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4$

Evaluate the exponents and the products

$(2x -3)^4 = 16x^4 + 96x^3 +216x^2 -216x + 81$

Hence, the value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

#SPJ1

8 0

2 years ago