Answer:
x=3,y=7
Step-by-step explanation:
8x+3y=45
2x+3y=27
8x-2x=6x
45-27=18
<u>6</u><u>x</u><u>=</u><u>1</u><u>8</u>
6. 6
x=3
2x+3y=27
2(3)+3y=27
6+3y=27
3y=27-6
<u>3</u><u>y</u> = <u>2</u><u>1</u>
3. 3
y=7
<h3>
Answer: 23</h3>
The three angles of any triangle always add to 180, so,
z+62+95 = 180
z+157 = 180
z+157-157 = 180-157 .... subtract 157 from both sides
z = 23
As a check,
z+62+95 = 23+62+95 = 180
so the answer is confirmed.
A.) Since there are no restrictions as to the dimensions of the candle except that their volumes must equal 1 cubic foot and that each must be a cylinder, we have the freedom to decide the candles' dimensions.
I decided to have the candles equal in volume. So, 1 cubic foot divided by 8 gives us 0.125 cubic foot, 216 in cubic inches.
With each candle having a volume of 216 cubic inches, I assign a radius to each: 0.5 in, 1.0 in, 1.5 in, 2.0 in, 2.5 in, 3.0 in, 3.5 in, and 4.0 in. Then, using the formula of the volume of a cylinder, which is:
V=pi(r^2)(h)
we then solve the corresponding height per candle. Let us let the value of pi be 3.14.
Hence, we will have the following heights (expressed to the nearest hundredths) for each of the radius: for
r=2.5 in: h=11.01 in
r=3.0 in: h= 7.64 in
r=3.5 in: h= 5.62 in
r=4.0 in: h= 4.30 in
r=4.5 in: h= 3.40 in
r=5.0 in: h= 2.75 in
r=5.5 in: h= 2.27 in
r=6.0 in: h= 1.91 in
b. each candle should sell for $15.00 each
($20+$100)/8=$15.00
c. yes, because the candles are priced according to the volume of wax used to make them, which in this case, is just the same for all sizes
Answer:
(3x - 1)(4x - 3)
Step-by-step explanation:
separating terms it will look like this
(3x - 1)(4x - 3)
when multiple each numbers you will see it will form up as 12x^2 -13x + 3
Step-by-step explanation:
By arc sum Postulate of a circle:
2 x + 3x + 4x = 360°
9x = 360°
x = 360°/9
x = 40°
3x = 3* 40° = 120°
By inscribed angle theorem:
By tangent secant theorem:
Since, measure of central angle is equal to the measure of its corresponding minor arc.
By angle sum Postulate of a triangle: