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7−5+3−1 With no solution

leva [86]

Answer:

-2

Step-by-step explanation:

7−5+3−1

using BODMAS

A is addition and it comes before subtraction

7−(5+3)−1

7-8-1

then solve

7 - 9 = -2

4 0

3 years ago

I am weighed on scales which have a 10% error, that is, the scales show me 10% heavier than my real weight. If I actually weigh

stiks02 [169]

Remember you said the scale shows you 10% heavier.

So that's an increase of 10%

So value = 10% + 100% = 110%

So scale would show 110% of 82

110% of 82

= (110/100) * 82

= 1.1 * 82

= 90.2

OR

We can simply find 10% of 82 and add it to the original 82.

10% of 82

(10/100) * 82

0.1 * 82 = 8.2

8.2 + 82 = 90.2 Same answer as before.

So scale shows 90.2 kg.

4 0

3 years ago

Read 2 more answers

Tomas reparte 9 kg de mandarinas en mallas de tres cuartos de kilo cada una . ¿Cuantas mallas obtiene?

MrRissso [65]

Responder:

12

Explicación paso a paso:

Dado que:

Kilogramo total de mandarina = 9 kg

Tamaño de cada distribución = 3/4 de kilo

Número de mallas:

Kilogramo / tamaño total por distribución

9 kg ÷ 3/4 kg

9 * 4/3

= (9 * 4) / 3

= 36/3

= 12

7 0

3 years ago

•Use the Pythagorean Theorem c^6 = a2+ b2 •Show you work to find each missing side •

zhannawk [14.2K]

Answer:

hypotenuse = 10

Step-by-step explanation:

If you can tell at first glance it is a 3,4,5 triangle (6,8,10)/2=(3,4,5). Then you know that c has to equal 5.

If not,

a^2+b^2=c^2

6^2+8^2=c^2

36+64=c^2

100=c^2

10=c

6 0

3 years ago

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$