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givi [52]
3 years ago
5

Bella has drawn a line to represent the parallel cross-section of the triangular prism. Is she correct? Explain

Mathematics
1 answer:
zepelin [54]3 years ago
3 0

Answer:

I think that the answer is D

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Complete the statements to determine the amount of BTUs needed to properly cool Arthur's apartment.
elena-14-01-66 [18.8K]

Answer:

1. 2,160ft^3

2. multiply the total volume by 2.5

3. 5,400 BTUs

Step-by-step explanation:

hope this helps

3 0
2 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10
matrenka [14]
D:y-10\geq0 \wedge y-2\geq0\\
D:y\geq10 \wedge y\geq2\\
D:y\geq10\\\\
\sqrt{y-10}=y-2\\
y-10=(y-2)^2\\
y-10=y^2-4y+4\\
y^2-5y+14=0\\
\Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\
\Delta
7 0
3 years ago
How many solutions does this system have?<br> y = -2x + 4<br> y = x^2 - 2x +4
AVprozaik [17]

Answer:

One Solution

Step-by-step explanation:

6 0
3 years ago
2/3 plus negative 1/3
vovikov84 [41]

2/3 + (-1/3) = 2/3 - 1/3 = 1/3

3 0
3 years ago
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