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torisob [31]
3 years ago
11

How would I put this equation into standard form for a parabola?

Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

fffffffffffffffffffffffffffffff

Step-by-step explanation:


You might be interested in
Lines CD and DE are tangent to circle A as shown below: If CE is 105 degrees, what is the measure of angle CDE?
Inessa [10]

Answer:

C

Step-by-step explanation:

∠CDE = 0.5( mEC - m CE )

The arcs CE and EC must add to 360°, thus

arc EC = 360° - 105° = 255°, hence

∠CDE = 0.5(255 - 105)° = 0.5 × 150° = 75° → C

6 0
3 years ago
Read 2 more answers
Melody had 45. She spent 32.75 on a blouse . Then her mother gave her 15.50. How much money does Melody have now ?
koban [17]

Answer:

Melody have now $27.75

Step-by-step explanation:

We will proceed to solve the problem in parts so that it can be better understand

so

1) Originally Melody had $45

2) She spent $32.75 on a blouse

so

In this moment Melody has --------> $45-$32.75=$12.25

3) Her mother gave her $15.50

so

In this moment Melody has --------> $12.25+$15.50=$27.75

therefore

Melody have now $27.75

5 0
3 years ago
C + 6 &lt; 7<br> what’s the answer??
Marrrta [24]

Answer:

c<1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP simple geometry problem
vlabodo [156]

Perimeter is adding the 3 sides together. Since both triangles have the same perimeter set both triangles to equal:


(x+3 + x+3 + x+3) = (x+3 + 2x-3 + x)

Simplify each side:

3x+9 = 4x

Subtract 3x from each side:

x=9



5 0
4 years ago
Use the WeierstrassM-test to show that each of the following series converges uniformly on the given domain:
ryzh [129]

Answer:

Step-by-step explanation:

Given a series \sum_{k=1}^\infty f(z), the Weierstrass M-test tell us that if we find a sequence of positive numbers M_n such that |f(z)|\leq M_n in a certain domain D, and the series \sum_{n=1}^\infty M_k converges, then the series \sum_{k=1}^\infty f_k(z) converges uniformly in the domain D.

So, our objective is to find the so called sequence M_k. The main idea is to bound the sequence of functions \frac{z^k}{z^k + 1}.

Now, notice that the values of z are always positive, so z^k is always positive, so z^k+1\geq 1 for all values of z in \overline{D}. Then,

\Big| \frac{z^k}{z^k + 1}\Big| \leq z^k,

because if we make the values of the denominator smaller, the whole fraction becomes larger.

Moreover, as z is in the interval [0,r], we have that z\leq r and as consequence |z^k|\leq r^k. With this in addition to the previous bound we obtain

\Big| \frac{z^k}{z^k + 1}\Big| \leq |z^k|\leq r^k.

With this, our sequence is M_k = r^k and the corresponding series is \sum_{k=1}^\infty r^k, which is a geometric series with ratio less than 1, hence it is convergent.

Then, as consequence of Weierstrass M-test we have the uniform convergence of the series in the given domain.

6 0
3 years ago
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