Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
72 m^2 (72 meters squared)
We’ll subtract the exponent in the denominator from the exponent in the numerator, keeping the base the same. Cant be simplified, because the base of the expression in the numerator is y and the base of the expression in the denominator is x.
285$ divided by 5$ = 57, 57 would be the correct answer.
Answer:
Step-by-step explanation:
560=3s+b
b.
560=3×150+b
b=560-450=110
when s=149,b=560-3×149=560-447=113
s=2,b=560-3×2=560-6=554
s=1,b=560-3×1=557
s=0,b=560-3×o=560
so domain of b={110,113,116,...,554,557,560}
