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Valentin [98]
3 years ago
7

Identify the number of zeros

Mathematics
1 answer:
mezya [45]3 years ago
7 0

Answer:

0

Step-by-step explanation:

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ew423q4rw32432ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph -2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2erw3r5432

Step-by-step explanation:

дешовок овц в гавне собак гандонов xddddddddddddddddddddddddddddddd

6 0
3 years ago
Find the circumference of the circle. Use 3.14 for pi. Just want to make sure my answer for question 7 is right.
leva [86]
The circumference is 2PieR, so we'd multiply 1.65 by 2, and get 3.3.
Afterwards, we multiply 3.3 by 3.14, which is 10.362. Your answer is incorrect.
4 0
3 years ago
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