1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fed [463]
3 years ago
7

Solve each system of inequalties by graphing.

Mathematics
1 answer:
nordsb [41]3 years ago
8 0

Start by graphing each line.

• Because the first inequality is smaller than, it will have a dotted (- - -) line.

• Because the second inequality is smaller than or equal to, it will have a solid line (---).

Then, plug in points to see where your shading will go. If the statement is true (x = x), you will shade that area along the line.

y  < 3x + 2

(0)  < 3(0) + 2

0  <  2

0 is less than 2.

Do the same step for the other equation. Your solution to the problem is any point that lies between the shading from both inequalities (where the blue and red meet).

You might be interested in
Help. Will mark brainiest
Nikitich [7]

Answer:

Step-by-step explanation:

The third, fifth and sixth expressions (from the top) are NOT polynomials, and the reason in each case is that the expression has one or more negative powers of x in it.

8 0
3 years ago
Edward wrote a pattern starting at 0 and following the rule "add 2." . Juan wrote a pattern starting at 0 and following the rule
julsineya [31]

Answer:

where are the patternes that are supposed to be shown?

Step-by-step explanation:

it says : Which pair of patterns below represents that of Edward and Juan?

but there are no patterns shown

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME !!
V125BC [204]

Answer:

\huge\boxed{\sf The\ co-efficient\ of\ x\ is\ -4.}

Step-by-step explanation:

Slope = m = -4

Y-intercept = c = -7 ( Because that is the point where x = 0 )

<u>Equation:</u>

\sf y = mx+c\\\\y = -4 x+(-7)\\\\y = -4x-7

So, The co-efficient of x is -4.

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
Event v occurs 28% of the time on Tuesdays.
vampirchik [111]

Answer:

68%

Step-by-step explanation:

Probability of occurrence of Event v = P(v) = 28% = 0.28

Probability of occurrence of both Events v and Event w together = P(v and w) = 19% = 0.19

We have to find what is the probability  that event w occurs with event v given that event v  occurs on a Tuesday. This is a conditional probability. In other words we have to find what is the probability of event w given that event v occurs of Tuesday. i.e we have to find P(w|v)

The formula to calculate this conditional probability is:

P(w|v) = \frac{P(v \cap w)}{P(v)}

Using the given values, we get:

P(w|v) = \frac{0.19}{0.28}\\\\ P(w|v) = 0.68\\\\ P(w|v) = 68\%

Therefore, the probability that even w will occur with event v given that event v occurs on Tuesday is 68%

7 0
2 years ago
If the working age population is 250 million, 170 million are employed and 9 million are unemployed, the unemployment rate is
mr Goodwill [35]

Answer:

5.0

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Other questions:
  • An airplane at 30,100 feet above the ground begins descending at the rate of 2150 feet per minute. Write and solve a linear equa
    11·1 answer
  • Show work and graph it
    10·1 answer
  • What is an adaptive test?
    11·2 answers
  • I need to know how to work it out and get the answer?!.​
    6·1 answer
  • Actors of her event Adventure book in one night and now she is on page 204 The Venture book has 590 Pages how many more pages do
    8·2 answers
  • This is the last question i have please help me
    13·2 answers
  • Please help with math,
    8·1 answer
  • Simplify the expression to a + bi form:<br> (-2 - 6i)?
    9·1 answer
  • Who is farther? a a Briel and Daniela are siblings. One day, Briel decided to go on a mountain climbing but Daniela went to the
    13·2 answers
  • Can someone help with explanation please:)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!