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fredd [130]
3 years ago
5

How is factoring a trinomial different than factoring a number?

Mathematics
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

Hope this answers the question.

Step-by-step explanation:

Factoring a number: If you use the number 10, for example, you have to find all the factors to factor it. 1, 2, 5, 10.

Factoring a trinomial: If you use the trinomial x^2 + 16 + 64, for example, to factor it you need to first find what numbers multiply up to 64 and also add up to 16. In this case, those numbers are 8, and so you get (x + 8)^2.

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Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.
SCORPION-xisa [38]

Answer:

The solutions are x=-3,\:x=3

Step-by-step explanation:

To factor this cubic polynomial x^3+3x^2-9x-27 you must:

  • Group the polynomial into two sections

x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)

  • Factor out -9 from (-9x-27)

(-9x-27)=-9\left(x+3\right)

  • Factor out x^2 from (x^3+3x^2)

(x^3+3x^2)=x^2\left(x+3\right)

x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)

  • Factor out common term x+3

-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)

x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)

  • Factor x^2-9

x^2-9=\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0

  • Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}

The solutions are

x=-3,\:x=3

3 0
3 years ago
Help me please<br> 3x+12=?
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Answer:

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All the dimensions of a pentagon were multiplied by the same factor, and area of the figure changed by a factor if 25. By what f
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Answer:

50

Step-by-step explanation:

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Mr. Voelz estimates that he will spend $10 on concessions at the basketball game. He actually spends $15. What is the percent er
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Answer:

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Step-by-step explanation:

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