Correct question:
An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?
Answer:
-53 feets
Step-by-step explanation:
Initial stop point = 25 feets below ground level
Further distance traveled = 28 feets below ground level
Final position in feet = Initial stop point + further distance traveled
Note : distances or point traveled below ground level or downward is represented as negative.
Final position in feets = (-25)feets + (-28)feets
Final position in feets = - 53 feets
- The volume of a medium box is 512 cubic inches.
- The ratio of the sides of the small box to the medium box is 1:2.
- The ratio of the area of the small box to the medium box is 1:4.
- The ratio of the volume of the small box to the medium box is 1:8.
<h3>What are the ratio of the small box to the medium box?</h3>
The first step is to determine the side lengths of the small box.
Side length = ∛64 = 4 in
Side lengths of the medium boxes = 4 x 2 = 8 inches
Volume of the medium box = 8³ = 256 cubic inches
The ratio of the sides of the small box to the medium box = 4 : 8 = 1:2.
The ratio of the area of the small box to the medium box= (4 x 4) : (8 x 8) = 1:4.
The ratio of the volume of the small box to the medium box = 4³ : 8³ = 1 : 8.
To learn more about the volume of a cuboid, please check: brainly.com/question/26406747
Answer:
-23/4 ft
Step-by-step explanation:
Combine -2 1/2 ft with -3 1/4 ft. The result will be -5 3/4 ft, or -23/4 ft.
Multiply what’s on the outside to the inside, the variable is always a lower case letter such as x,
Answer:
it is five
Step-by-step explanation:
5v-2=8 then v=x2 because 5x2=10-2=8
so 7v-9=5
