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2 years ago

Factorise fully -x - 8

Mathematics

1 answer:

natta225 [31]2 years ago

3 0

Answer:

x = -8 please mark brainliest

Step-by-step explanation:

Pull out like factors :

-x - 8 = -1 • (x + 8)

Equation at the end of step 1 :

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : -x-8 = 0

Add 8 to both sides of the equation :

-x = 8

Multiply both sides of the equation by (-1) : x = -8

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Belinda is jumping on a trampoline. She jumps up with an initial velocity (v0) of 17 feet per second. The function d(t) = v0t-16

g100num [7]

Answer:

<em>1.0625 seconds</em>

Step-by-step explanation:

Given that:

Initial velocity of Belinda, $v_0=17\ ft/sec$

Height in feet of Belinda above the trampoline is given as the formula:

$d(t) = v_0t-16t^2$

Where $t$ is the time in seconds.

To find:

Time taken by Belinda to come back to trampoline = ?

Solution:

When Belinda will come back to trampoline, the height will be zero.

Putting $d(t) =0$

We have the equation as:

$0 = 17t-16t^2\\\Rightarrow 16t^2-17t=0\\\because t\neq0\\\Rightarrow 16t=17\\\Rightarrow t=\dfrac{17}{16}\\\Rightarrow t =1.0625\ seconds$

Therefore, the answer is: <em>1.0625 seconds</em>

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2 years ago

BRAINLIEST FOR THE CORRECT AWNSER!! PLEASE PUT THE LETTER AWNSER AND EXPLAIN DO NOT LIE THANK YOU What is the goal of a proof by

babymother [125]

Answer:

Step-by-step explanation:

We assume the opposite and then get to a point where we get a false statement. That proves that the the opposite of the opposite (What we originally wanted to prove) is true.

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3 years ago

Read 2 more answers

A group of tourists spend $168 to rent snorkels and find. A total of 10 snorkels and 12 pairs of fins are rented. Renting a snor

WITCHER [35]

Answer:

Cost to a rent a snorkel $=\$ 12$ , Cost on 10 rent snorkel $=\$ 120$

Step-by-step explanation:

Given,

Tourist spend on rent snorkel and fin= $\$ 168$

10 snorkel and 12 pairs of fin

Let the cost to rent a snorkel be = $\$$ x

and cost of a pair of fin is = $\$$ y

x=3y (given condition)

$10x+12y=168$

$10\times 3y+12y=168$

$30y+12y=168$

$42y=168$

$y=168/42$

$y=4$

Cost of a pair of fin= $y=\$ 4$

$x=3y$

$x=3\times 4$

$x=12$

Cost of rent a snorkel $=\$ 12$

Total cost of a rent snorkel

$=10\times 12$

= $\$ 168$

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2 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

2 years ago

At the North campus of a performing arts school 30% of students are music majors at the South campus 80% of the students are mus

OLEGan [10]

Answer:

It should be option B

Step-by-step explanation:

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3 years ago