3 years ago

Please help urgent!!!!! Will mark brainlest or something like that

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

4 0

Answer:

im sry could u pls rewrite the expression?

Step-by-step explanation:

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Answer and Step-by-step explanation:

<u>Trigonometric Function (These only work for right triangles):</u>

SOH-CAH-TOA

S = Sine = sin

C = Cosine = cos

T = Tangent = tan

O = Opposite (side)

H = Hypotenuse (side)

A = Adjacent (side)

SOH = sin(angle) = $\frac{opposite}{hypotenuse}$

CAH = cos(angle) = $\frac{adjacent}{hypotenuse}$

TOA = tan(angle) = $\frac{opposite}{adjacent}$

1. sinQ (Q is the angle) = $\frac{14}{50} = \frac{7}{25} = 0.28$

Use Pythagorean Theorem to find side PQ. $14^{2} + PQ^{2}= 50^{2} \\PQ^{2} = 2304\\PQ = 48$

2. cosQ = $\frac{48}{50} = \frac{24}{25} = 0.96$

3. tanQ = $\frac{14}{48} = \frac{7}{24} = 0.29$

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Answer:

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Step-by-step explanation:

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