To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
<u>Rectangle (a)</u>
<u>Rectangle (b)</u>
<u>Rectangle (c)</u>
<u>Rectangle (d)</u>
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
I think it's 115
180-65= 115=<BCD
The root of this parabola are x'=2 & x'' = 4, these are the value of x intercepts. The midpoint = (4-2)/2 = 1
5(x + 10)?  A.5x + 10 B.5x + 10x C.5x + 50 D.5 + x + 10.