Answer:
Ye you got it right
Step-by-step explanation:not that hard
ITS RIGHT
Answer:
B. This is a reflection of the oval.
Step-by-step explanation:
The second oval is almost a perfect copied image of the first but only flipped over the y axis vertically, making this a reflection of the oval.
To solve this problem you must apply the proccedure shown below:
1. You have the following inverse trigonometric function given in the problem above:
![y=arcsin(- \sqrt{3} /2) ](https://tex.z-dn.net/?f=y%3Darcsin%28-%20%5Csqrt%7B3%7D%20%2F2%29%20%0A%0A)
2. By definition, you have that
![y=arcsinx ](https://tex.z-dn.net/?f=y%3Darcsinx%0A)
is equivalent to
![siny=x ](https://tex.z-dn.net/?f=siny%3Dx%0A)
and
![sin(-x)=-sin(x)](https://tex.z-dn.net/?f=sin%28-x%29%3D-sin%28x%29)
, therefore:
![-siny=( \sqrt{3}/2)](https://tex.z-dn.net/?f=-siny%3D%28%20%5Csqrt%7B3%7D%2F2%29)
4. The value of the sine of
![\sqrt{3}/2](https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%2F2)
is
![\pi/3](https://tex.z-dn.net/?f=%20%5Cpi%2F3)
, therefore:
The answer is:
Answer:
AB = DC So ∠A and ∠D are bigger then 90%