Answer:
int counter = 0;
String userInput = "";
while (userInput != "stop") {
print "What pet do you have? ";
userInput = readInputLine();
if (userInput != "stop" ){
counter = counter + 1;
print "\nYou have one ";
print userInput;
print ". Total # of Pets: ";
print counter;
}
}
Explanation:
not sure what programming language you use, therefore the answer is pseudocode but it should give you an idea how to implement a piece of code for this problem.
Also, from the way you described the exercise I'm not sure if you always are supposed to reply with "you have one" + the pet or if you should count how often the same pet was entered.
Yeh it’s becoz they work with hardware that’s why
Answer:
Priority programming is a process programming method based on priority. In this technique, the developer chooses the tasks to work according to priority, which is different from other types of programming, for example, a simple round-robin.
On UNIX and many other systems, higher priority values represent lower priority processes. Some of the systems, such as Windows, use the opposite convention: a higher number means a higher priority
<h3>Explanation:
</h3>
Priorities can be dynamic or static. Static priorities are assigned during creation, while dynamic priorities are assigned according to the behavior of the processes while they are in the system. To illustrate, the planner could favor intensive input / output (I / O) tasks, allowing expensive requests to be issued as soon as possible.
Priorities can be defined internally or externally. Internally defined priorities make use of a measurable amount to calculate the priority of a given process. On the contrary, external priorities are defined using criteria beyond the operating system (OS), which may include the importance of the process, the type and sum of the resources used for the use of the computer, user preferences , trade and other factors such as politics etc.
i hope this is right lol
