Answer:
Following are the program in the C++ Programming Language.
//set header file
#include <iostream>
//set namespace
using namespace std;
//define class
class format
{
//set access modifier
public:
//set string type variable
string res;
//define function
void names(string first_name, string last_name)
{
//set if-else if condition to check following conditions
if(first_name.length()>0 && last_name.length()>0)
{
res="Name: "+last_name+", "+first_name;
}
else if(first_name.length()>0 and last_name.length()==0)
{
res="Name: "+first_name;
}
else if(first_name.length()==0 and last_name.length()==0)
{
res="";
}
}
//define function to print result
void out(){
cout<<res<<endl;
}
};
//define main method
int main() {
//set objects of the class
format ob,ob1,ob2;
//call functions through 1st object
ob.names("John","Morris");
ob.out();
//call functions through 2nd object
ob1.names("Jhon","");
ob1.out();
//call functions through 3rd object
ob2.names("", "");
ob2.out();
}
<u>Output</u>:
Name: Morris, John
Name: Jhon
Explanation:
<u>Following are the description of the program</u>:
- Define class "format" and inside the class we define two void data type function.
- Define void data type function "names()" and pass two string data type arguments in its parameter "first_name" and "last_name" then, set the if-else conditional statement to check that if the variable 'first_name' is greater than 0 and 'last_name' is also greater than 0 then, the string "Name" and the following variables added to the variable "res". Then, set else if to check that if the variable 'first_name' is greater than 0 and 'last_name' is equal to 0 then, the string "Name" and the following variable "first_name" added to the variable "res".
- Define void data type function "out()" to print the results of the variable "res".
- Finally, we define main method to pass values and call that functions.
Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
Answer:
Interface
Explanation:
Java does not supports multiple inheritance by class, but we can implement multiple inharitacnce in java using interface, with interface we uses implements keyword.
Example-
Declare interface like below code -
interface parent{
}
and use in child class like below code -
class Child1 implements interface{
}
class Child2 implements interface{
}
Answer:
1.Choose a clear central message 2. Embrace conflict 3.Have a clear structure
Explanation:
Answer:
Top to bottom Answer in order
#1 hardskills
#2 goal
#3 value
#4 soft skills
#5 on the job training
#6 self training
