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PSYCHO15rus [73]
4 years ago
10

I don't understand this pls help

Mathematics
1 answer:
Nitella [24]4 years ago
6 0

Answer:

1

Step-by-step explanation:

Solve. Remember to follow PEMDAS.

PEMDAS  is the order of operation, and =

Parenthesis

Exponent (& Roots)

Multiplication

Division

Addition

Subtraction

First, divide 54 with -6:

54/(-6) = -9

Next, combine the terms.

10 + (-9) = 10 - 9 = 1

1 is your answer.

~

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Use the given area of the base and the height to find the volume of the right rectangular prism, in cubic units.
Semenov [28]

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3 years ago
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I need help solving for X
Vitek1552 [10]

Answer:

x = 35

Step-by-step explanation:

angles in a triangle add up to 180.

x + 11 + 3x + 1 + x - 7 = 180

combine like terms

5x + 5 = 180

subtract 5 from both sides of the equation

5x + 5 - 5 = 180 - 5

5x = 180 - 5

5x = 175

divide both sides of the equation by 5

5x/5 = 175/5

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3 years ago
Find the average of the following numbers: 2 and 4
Marrrta [24]
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3 years ago
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If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

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The interval(s) for which the function shown below is increasing
Oduvanchick [21]

Answer:

everywhere except between 2 and 5

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Step-by-step explanation:

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