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Yuri [45]
3 years ago
5

What is the net ionic charge for an oxygen ion

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

2-

Step-by-step explanation:

An O atom is neutral because it has the same  number of protons as electrons.

O is in Group 16, so it <em>adds two electrons</em> to get a complete octet.

Since it has two extra electrons, the charge on an oxygen ion is 2-.


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Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
coldgirl [10]

Answer :

a. The oxidizing agent is: BH_4^-

b. The reducing agent is: ClO_3^-

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : BH_4^-\rightarrow H_2BO_3^-

Reduction : ClO_3^-\rightarrow Cl^-

Now balance oxygen atom on both side.

Oxidation : BH_4^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-  

Now balance hydrogen atom on both side.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-

Now balance the charge.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-

Reduction : ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-

Reduction : 4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-

The balanced chemical equation in acidic medium will be,

6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-

3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-

In the redox reaction, ClO_3^- act as oxidizing agent and BH_4^- act as an reducing agent.

7 0
3 years ago
If the [H+] is 3.5x10-4, what is the [OH-]?
slava [35]

Answer:

2.90 x 10⁻¹¹moldm⁻³

Explanation:

Given parameters:

[H⁺]  = 3.5 x 10⁻⁴mol/dm³

Unknown

[OH⁻]  = ?

Solution;

The ionic product of water can be used to solve this problem. It has been experimentally determined to be  1 x 10⁻¹⁴mol² dm⁻⁶

             [H⁺] [OH⁻]  = 1 x 10⁻¹⁴

Therefore;

             [OH⁻]   = \frac{1  x 10^{-14} }{H}    = \frac{1  x  10^{-14} }{3.5 x 10^{-4} }   = 0.29 x 10⁻¹⁰moldm⁻³

                                                            = 2.90 x 10⁻¹¹moldm⁻³

8 0
3 years ago
Chemical or physical change? and what made you think such?​
spayn [35]

Answer:

it's a chemical change and an electrolytic reaction

8 0
4 years ago
Read 2 more answers
what is the amount of heat energy released when 50.0 grams of water is cooled from 20.0 degrees Celcius to 10.0 degrees celcius
andre [41]

Answer:

The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to  - 2093 J.

Explanation:

Given data:

Mass of water = 50 g

Initial temperature= T1 = 20°C

Final temperature= T2 = 10°C

Specific heat of water= c = 4.186 J/g. °C

Amount of heat released = Q= ?

Solution:

Formula:

Q = m. C.  ΔT

ΔT = T2 - T1

ΔT = 10°C - 20°C

ΔT = -10°C

Now we will put the values in formula.

Q = m. C.  ΔT

Q = 50 g .  4.186 J/g. °C . -10°C

Q =  - 2093 J

The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to  - 2093 J.

6 0
3 years ago
Read 2 more answers
The enthalpy change of reaction is also called
Vikentia [17]
C) Heat of the reaction.
7 0
3 years ago
Read 2 more answers
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