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Pepsi [2]
2 years ago
15

What is the area of the figure? A.234 in.^2 B.315 in.^2 C.225 in.^2 D.252 in.^2

Mathematics
1 answer:
saul85 [17]2 years ago
5 0

Let's imagine we enclosed the entire shape in a 15 inch wide, 21 inch tall rectangle, area 315 sq inches.

From that rectangle we have to take away the 3x6 bottom left corner, and a strip 21-6=15 inches long and 3 inches wide on the right.

A = 15×21 - 3×6 - 3×15 = 315 - 63 = 252 sq in

Answer: D.   252 inches squared, last choice

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A rectangle has a perimeter of 16 feet. What is a possible length and width for the rectangle? A rectangle has a perimeter of 16
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3 years ago
In the figure to the right, AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Find the perimeter of the figu
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Answer:

<em>P= 5.5 cm</em>

Step-by-step explanation:

<u>The Perimeter of Plane Shapes</u>

If we are given a plane shape, the perimeter is the measurement of the boundary of it. In case the shape is made of lines, the perimeter is the sum of the lengths of all of them.

We are given an irregular shape, we only need to add all the sides. But we don't have all the individual sides. Let's write the expression for the perimeter.

P=AE+ED+DC+CB+BA

We have: AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Note we don't have AE or DC, but we have their sum, so

P=AE+DC+ED+CB+BA

Recall that AB=BA, the order of the letters is not important. The perimeter is

\displaystyle P=1\frac{1}{5}+1\frac{1}{4}+1\frac{3}{10}+1\frac{3}{4}

We add the integer parts separate from the fractions

\displaystyle P=4+\frac{1}{5}+\frac{1}{4}+\frac{3}{10}+\frac{3}{4}

Now we use the common denominator (Least Common Multiple or LCM ) which is 20:

\displaystyle P=4+\frac{4+5+6+15}{20}

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\displaystyle P=4+\frac{30}{20}

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\displaystyle P=4+\frac{3}{2}

\displaystyle P=\frac{11}{2}=5.5\ cm

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3 years ago
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